Normally you would find the critical value when given the p value and the test statistic.
A p-value is the probability of obtaining a test statistic as extreme or more extreme than the one actually obtained if the null hypothesis were true. If this p-value is less than the level of significance (usually set by the experimenter as .05 or .01), we reject the null hypothesis. Otherwise, we retain the null hypothesis. Therefore, a p-value of 0.66 tell us not to reject the null hypothesis.
If the probability of an event occurring is p, then 1-p represents the probability of the same event not occurring. The value of p must lie between 0 and 1.
The p-value is the probability of any event or the level of significance for any statistical test. The z-score is a transformation applied to a Random Variable with any Normal distribution to the Standard Normal distribution.
p value are used when comparing the likelihood of a stated [null] hypothesis being true against a stated alternative. It is a measure of the probability with which an observation which is at least as extreme as that observed will occur even though the null hypothesis is true.
The value of p in the equation 9(p-4) - 18 is 6. When we simplify the equation, 9(p-4) - 18 becomes 9p - 36 - 18, which further simplifies to 9p - 54. To find the value of p, we set this equal to 0 and solve for p, 9p - 54 = 0, which gives p = 6.
-9p-17=8 -17=8+9p 9p=-17-8 9p= -25 p=-25/9
Evaluate 9p + 33 for p = 5
9p + 27 = 9(p + 3)
p2 + 9p + 18/ p + 6(p + 6)(p + 3)/ p + 6(p + 6)(p + 3)/ p + 6p + 3
p = -3
-14 + 3p = -9p - 21 add 14 and 9p to both sides, then 12p = -7 p = -7/12
It is a linear equation in the one variable, p.
9p - 5
4p - 12 = 3p - 8 - 9p 4p - 3p + 9p = -8 + 12 10p = 4 p = 0.4 (or 2/5)
11 - 9p.
3p + 6p = (3 + 6)p = 9p