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Three fair coins are tossed determine the probability of the following event exactly two coins land on heads?
The sample space is 23 or 8; which can be listed out as: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. There are 2 of the 8 that have exactly 2 heads; so the probability of exactly two coins landing on heads is 2/8 or 1/4.
Seven coins are tossed What is the probability of 3 heads or 2 tails?
The probability of one event or the other occurring is the probability of one plus the probability of the other. The probability of getting 3 heads is the probability of 3 heads (1/23) multiplied by the probability of 4 tails (1/24) multiplied by the number of possible ways this could happen. This is 7c3 or 35. Thus the probability of 3 heads is 0.2734375. The probability of 2 tails is the probability of 2 tails (1/22) multiplied by the probability of 5 heads (1/25) multiplied by the number of ways this could happen. That is 7c5 or 21. Thus the probability of 2 tails is 0.1640625 The probability of one or the other is the sum of their probabilities: 0.1640625 + 0.2734375 = 0.4375 Thus the probability of getting 3 heads or 2 tails is 0.4375.
What is the probability of an event b that impossible?
The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.
What is the getting one tail when two coins are tossed simultaneously?
It is the event that one of the two coins lands showing tails and the other shows heads.
What are complementary events in probability?
Complementary events are events that are the complete opposite. The compliment of event A is everything that is not event A. For example, the complementary event of flipping heads on a coin would be flipping tails. The complementary event of rolling a 1 or a 2 on a six-sided die would be rolling a 3, 4, 5, or 6. (The probability of A compliment is equal to 1 minus the probability of A.)
What is the multiplication rule?
States that to determine a probability, we multiply the probability of one event by the probability of the other event. Ex: Probability that two coins will land face heads up is 1/2 x 1/2 = 1/4 .
Three fair coins are tossed determine the probability of the following event exactly two coins land on heads?
The sample space is 23 or 8; which can be listed out as: HHH, HHT, HTH, HTT, THH, THT, TTH, TTT. There are 2 of the 8 that have exactly 2 heads; so the probability of exactly two coins landing on heads is 2/8 or 1/4.
writer sample space associated with the experiment of tossing 3 coins at the time and the event of getting heads from the first 2 coins.aslo find the correspondind probability?
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Seven coins are tossed What is the probability of 3 heads or 2 tails?
The probability of one event or the other occurring is the probability of one plus the probability of the other. The probability of getting 3 heads is the probability of 3 heads (1/23) multiplied by the probability of 4 tails (1/24) multiplied by the number of possible ways this could happen. This is 7c3 or 35. Thus the probability of 3 heads is 0.2734375. The probability of 2 tails is the probability of 2 tails (1/22) multiplied by the probability of 5 heads (1/25) multiplied by the number of ways this could happen. That is 7c5 or 21. Thus the probability of 2 tails is 0.1640625 The probability of one or the other is the sum of their probabilities: 0.1640625 + 0.2734375 = 0.4375 Thus the probability of getting 3 heads or 2 tails is 0.4375.
If you toss 4 coins what is the probability of getting two heads or two tails?
When tossing 4 coins, there are a total of (2^4 = 16) possible outcomes. The combinations for getting exactly 2 heads (and consequently 2 tails) can be calculated using the binomial coefficient, which gives us (\binom{4}{2} = 6) ways. Therefore, the probability of getting exactly 2 heads is ( \frac{6}{16} = \frac{3}{8} ). Since getting 2 heads and 2 tails are the same event, the total probability of getting either 2 heads or 2 tails is also (\frac{3}{8}).
What is the probability of tossing a coin three times and getting it on heads each time?
Each toss has a 1/2 probability of getting heads. Each toss is an independent event. So three heads in a row (heads AND heads AND heads) would have a probability of:1/2 * 1/2 * 1/2 = (1/2)^3 = 1/(2^3) = 1/8 = 12.5%
Would you expect the probability for the simple event rolling a 6 to be greater than or less than the probability of the compound event rolling a 6 and getting heads on a coin?
The probability of rolling a 6 on a fair six-sided die is ( \frac{1}{6} ). For the compound event of rolling a 6 and getting heads on a coin, the probability is ( \frac{1}{6} \times \frac{1}{2} = \frac{1}{12} ). Since ( \frac{1}{6} ) is greater than ( \frac{1}{12} ), we would expect the probability of rolling a 6 to be greater than the probability of the compound event.
What is the probability of an event b that impossible?
The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.
What is the probability of a coin landing on heads when it is flipped 100 times?
The probability of landing on heads at least once is 1 - (1/2)100 = 1 - 7.9*10-31 which is extremely close to 1: that is, the event is virtually a certainty.
What is the probablity of an event that is impossible?
The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.The probability of an impossible event is 0.
What is the probability of a independent event is going to happen?
If it's an independent event then it's probability does not depend on preceding events. For example, if I flip a coin twice the probability that the coin will show 'heads' the second time is independent of what happened the first time; it's just 1/2.
What is the getting one tail when two coins are tossed simultaneously?
It is the event that one of the two coins lands showing tails and the other shows heads.
