1 TBMS, or 1 Terabyte Management System, typically refers to a storage or data management solution capable of handling and organizing up to one terabyte of data. It can be utilized in various contexts, such as database management, cloud storage, or data analytics. The system is designed to efficiently manage, retrieve, and process large amounts of information, ensuring data integrity and accessibility.
It is spelled "a-n-t-i-d-i-s-e-s-t-a-b-l-i-s-h-m-e-n-t-a-r-i-a-n-i-s-m".
// transpose for the sparse matrix void main() { clrscr(); int a[10][10],b[10][10]; int m,n,p,q,t,col; int i,j; printf("enter the no of row and columns :\n"); scanf("%d %d",&m,&n); // assigning the value of matrix for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("a[%d][%d]= ",i,j); scanf("%d",&a[i][j]); } } printf("\n\n"); //displaying the matrix printf("\n\nThe matrix is :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { printf("%d\t",a[i][j]); } printf("\n"); } t=0; printf("\n\nthe non zero value matrix are :\n\n"); for(i=1;i<=m;i++) { for(j=1;j<=n;j++) { // accepting only non zero value if(a[i][j]!=0) { t=t+1; b[t][1]=i; b[t][2]=j; b[t][3]=a[i][j]; } } } printf("a[0 %d %d %d\n",m,n,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,b[i][1],b[i][2],b[i][3]); } a[0][1]=n; a[0][2]=m; a[0][3]=t; int s[10],u[10]; if(t>0) { for(i=1;i<=n;i++) { s[i]=0; } for(i=1;i<=t;i++) { s[b[i][2]]=s[b[i][2]]+1; } u[1]=1; for(i=2;i<=n;i++) { u[i]=u[i-1]+s[i-1]; } for(i=1;i<=t;i++) { j=u[b[i][2]]; a[j][1]=b[i][2]; a[j][2]=b[i][1]; a[j][3]=b[i][3]; u[b[i][2]]=j+1; } } printf("\n\n the fast transpose matrix \n\n"); printf("a[0 %d %d %d\n",n,m,t); for(i=1;i<=t;i++) { printf("a[%d %d %d %d\n",i,a[i][1],a[i][2],a[i][3]); } getch(); }
The correct spelling is 'A-n-t-i-d-i-s-e-s-t-a-b-l-i-s-h-m-e-n-t-a-r-i-a-n-i-s-m'.
1 m/s² (1 metre per second per second) is a measure of acceleration, NOT speed. Assuming you mean a swim rate of 1.0 m/s (1 metre per second), then: time = distance ÷ speed = 900 m ÷ 1 m/s = 900 s 60 s = 1 min → 900 s = 900 ÷ 60 min = 15 minutes ---------------------------------- Assuming you really do mean that you swim with a constant acceleration of 1 m/s² and you start at 0 m/s, then: s = ut + ½at² s = 900 m u = 0 a = 1 m/s² t = unknown → 900 m = 0 m/s × t + ½ × 1 m/s² × t² → 900 m = ½t² → t² = 1800 s² → t ≈ 42.43 s If you start at 0 m/s and accelerate at 1 m/s², then it will take approx 42.43 seconds to cover 900 m.
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern S-B-T--M. That is, eight letter words with 1st letter S and 3rd letter B and 5th letter T and 8th letter M. In alphabetical order, they are: sybotism
According to SOWPODS (the combination of Scrabble dictionaries used around the world) there are 1 words with the pattern B-S-M---T. That is, nine letter words with 1st letter B and 3rd letter S and 5th letter M and 9th letter T. In alphabetical order, they are: bosomiest
T. B. M. has written: 'Slum life in Edinburgh, or, Scenes in its darkest places' -- subject(s): Poor, Social conditions, Slums
Suppose the points are P = (r,s) and Q = (t,u) Then gradient of PQ = (u - s)/(t - r) = m, say. Let Z = (x,y) be any point on the line. Then gradient ZP also = m that is (y - s)/(x - r) = m Equating the two expressions for m, (y - s)/(x - r) = (u - s)/(t - r) or y - s = (x - r)*(u - s)/(t - r) y = (x - r)*(u - s)/(t - r) + s = x*m - r*m - s This is of the form y = mx + b, where m is as defined above and b = -r*m + s
Holy cow what the heck does that mean?! i s o y m b u h t a e i r y s
b w t c t s m w
the best site go here h t t p s : / / y a z i n g . c o m / de a l s / b l u e h o s t / d a m o n t e 1 k
Use the formula a^2 - b^2 = (a -b)(a + b). So: t^2 - (t - 1)^2 = [t - (t -1)][t + (t -1)] Now you can work and simplify the given expression. =(t - t +1)(t + t -1) =(1)(2t -1) = 2t -1