Suppose the middle one is 3x, then the other two are 3x-3 and 3x+3.
Their product is
(3x-3)*3x*(3x+3) = 3x*(3x-3)*(3x+3) = 27x(x-1)*(x+1) = 27x*(x2-1)
So 27x*(x2-1) = 648
x*(x2-1) = 648/27 = 24
ie x3 - x - 24 = 0
or x3 - 3x2 + 3x2 - 9x + 8x - 24 = 0
ie (x - 3)(x2 + 3x + 8) = 0
The only integer solution is x = 3
So the three numbers are 3*(3-1), 3*3 and 3*(3+1) = 6, 9 and 12.
sorry there is no times table that all have odd number.
0,6,18,36,60,90,126,168, etc
They are: 38 times 39 = 1482
They are: 85 times 86 = 7310
They are: 95 times 96 = 9120
They are 26 times 27 = 702
The two consecutive numbers that have a product of 4711 are 68 and 69. This can be determined by solving the equation ( n(n + 1) = 4711 ). When you calculate ( 68 \times 69 ), it equals 4711.
They are 6 times 8 = 48
The number is 231.
Yes because at least one of the consecutive numbers will be even, and if you times anything by an even number, the answer will always be even
They are -7 and -5.
17 and 19.