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This isn't hard to figure out if you know how far you want the base of the ladder from the wall. All you have to do is use the Pythagorean Theorem. The theorem is A2 + B2 = C2. A and B are the short sides and C is the hypotenuse (the side opposite the right angle). When dealing with a ladder, the ladder is the hypotenuse, or the C in the equation. Another way to put the formula is to multiply A by itself and B by itself, add them together, then take the square root of the result.
Decide how far you want the base of the ladder from the building. Multiply that by itself then add that to 169 (that is the square of 13). Then take the square root of that and you get the ideal ladder height. Lets assume 5 feet from the wall. The square of that is 25. 169 plus 25 gives 194. The square root of 194 is 13.928, and we would round up to 14 feet.
If you mean a step ladder, and you are trying to reach a ceiling, then you would need roughly the height of the room minus your own height. You might want to add a tad more. You could make it shorter, but that would not be wise, since you should always avoid the top two steps if possible.
What else can I help you with?
How long must a ladder be to reach the top of a 20 foot wall if the ladder and the wall form a 32 degree angle?
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
A ladder rests against a wall the top of the ladder reaches 15 feet up the wall and makes an angle of 53 with the wall how long is the ladder?
If the wall is straight and the ground level then this is an outline of a right angle-triangle. If the top of the ladder makes an angle of 530 with the wall then the bottom of the ladder must make 370 to the ground. Use the sine ratio to find the length of the ladder (which will be the hypotenuse) sin = opp/hyp rearranged to hyp = opp/sin hyp = 15/sin370 = 24.92460212 feet So the length of the ladder is 25 feet correct to the nearest foot.
How many feet from the base must a 39-foot ladder be placed so that the top of the ladder will reach a point on the house 36 feet from the ground?
Use Pythagoras h^(2) = H^(2) + b^(2) h(hypotenuse is the ladder length at 39 ft. H is wall height which is 36 ft. Substitute 39^(2) = 36^(2) + b^(2) Algebraically rearrange b^(2) = 39^(2) - 36^(2) b^(2) = ( 39 - 36)(39 + 36) b^(2) 3(75) b^(2) = 225 Square root BOTH sides b = 15 ft . The foot of the ladder should 15feet from the base of the house wall .
How long must a ladder be if it is to be leaned against a house at a point 9 feet above the ground resting at least 3 feet from the bottom edge of the wall?
This describes a right triangle. This triangle has a base (X ) of 3 ft, a opposite side ( Y) of 9 ft. So, you are looking for the hypothenuse. Use the Pythagoreum theory. In this case. Your ladder length is called H. H^2 = X^2 + Y^2 H = sqrt X^2 + Y^2
Is angle-angle-side a correct property of concurrency of triangles?
As long as the sides correspond then yes. The other three are: Side-Side-Side Side-Angle-Side - the angle *MUST* be between the two sides Right angle-Hypotenuse-Side
How long must a ladder be to reach the top of a 20 foot wall if the ladder and the wall form a 32 degree angle?
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
How far up a wall will a 12m ladder reach If the foot of the ladder must be 4m from the base of the wall?
16
How long must a ladder be to reach the top of a twenty foot wall if the ladder and the wall for a 32 degree angle?
Twenty divided by the cosine of 32 gives you 23.584 ft
A window sill is 12 feet above the ground How far must a ladder extend to reach the sill if the foot of the ladder is 5 feet from the building?
17
How long must a ladder be to reach the top of a 20' wall if the ladder and the wall form a 32 angle at the top?
23.53
How long must a ladder be to reach the top of a 20' wall if the ladder and the wall form a 32 degree angle (at the angle)?
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
How long must a ladder be to reach the top of a 20' wall if the ladder and the wall form a 32 degree angle at the top?
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
How long must a ladder be to reach to top of a 20 foot wall if the ladder and the top wall form a 32 degree angle at the top in a plus?
The ladder forms the hypotenuse (r) and the wall forms the vertical (y) of a right triangle. sin theta = y / r the angle at the bottom is (90 - 32) = 58 sin 58 = 20 / r r = 20 / sin 58 = 23.583568067241928552025478405751 feet ladder must be about (rounding) 23.6 feet long.
How long must a ladder be to reach the top of a 20 foot wall if the ladder and the wall form a 32 degree angle at the top?
23.58 feetA+no its not i just tryed it so yea get your facts right before putting them on herebut i dont even know this so srry for the ppl look for it
A 5 foot ladder is leaning against a 4 foot wall how far must the bottom of the ladder be from the base of the wall so that the top of the ladder rests on the top of the wall?
1 i think other people feel free to change this
Can a roofer who wants to repair your roof that is 28 feet above the ground level use a 28 foot ladder?
No. since the ladder must be on an angle it must have room so that the length of the ladder is equal to the 282 + (distance between bottom of ladder and house)2.
Can a roofer who wants to repair your roof that is 28 foot above the ground level use a 28 feet ladder?
No. since the ladder must be on an angle it must have room so that the length of the ladder is equal to the 282 + (distance between bottom of ladder and house)2.
