This isn't hard to figure out if you know how far you want the base of the ladder from the wall. All you have to do is use the Pythagorean Theorem. The theorem is A2 + B2 = C2. A and B are the short sides and C is the hypotenuse (the side opposite the right angle). When dealing with a ladder, the ladder is the hypotenuse, or the C in the equation. Another way to put the formula is to multiply A by itself and B by itself, add them together, then take the square root of the result.
Decide how far you want the base of the ladder from the building. Multiply that by itself then add that to 169 (that is the square of 13). Then take the square root of that and you get the ideal ladder height. Lets assume 5 feet from the wall. The square of that is 25. 169 plus 25 gives 194. The square root of 194 is 13.928, and we would round up to 14 feet.
If you mean a step ladder, and you are trying to reach a ceiling, then you would need roughly the height of the room minus your own height. You might want to add a tad more. You could make it shorter, but that would not be wise, since you should always avoid the top two steps if possible.
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
If the wall is straight and the ground level then this is an outline of a right angle-triangle. If the top of the ladder makes an angle of 530 with the wall then the bottom of the ladder must make 370 to the ground. Use the sine ratio to find the length of the ladder (which will be the hypotenuse) sin = opp/hyp rearranged to hyp = opp/sin hyp = 15/sin370 = 24.92460212 feet So the length of the ladder is 25 feet correct to the nearest foot.
Well, using a^2 + b^2 = c^2, where a and b are the legs and c is the hypotenuse, you need to square 39 and 36. Then your equation should look like a^2 +1296 = 1521, then solve for a^2, getting the variable by itself, so you have a^2 = 225. Then take the square root of both sides leaving you with a= 15. So, the ladder must be placed 15 feet from the base of the house.
This describes a right triangle. This triangle has a base (X ) of 3 ft, a opposite side ( Y) of 9 ft. So, you are looking for the hypothenuse. Use the Pythagoreum theory. In this case. Your ladder length is called H. H^2 = X^2 + Y^2 H = sqrt X^2 + Y^2
As long as the sides correspond then yes. The other three are: Side-Side-Side Side-Angle-Side - the angle *MUST* be between the two sides Right angle-Hypotenuse-Side
Hypotenuse = 20/sin580 = 23.58356807 Length of ladder: rounded to 23.584 feet
16
Twenty divided by the cosine of 32 gives you 23.584 ft
17
23.53
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
Then an angle of 58 degrees will be at the bottom of the ladder. Use trigonometry and the sine ratio: sin = opp/hyp and hyp = opp/sin hyp = 20/sin(58) = 23.58356807 length of ladder = 24 feet to the nearest foot
The ladder forms the hypotenuse (r) and the wall forms the vertical (y) of a right triangle. sin theta = y / r the angle at the bottom is (90 - 32) = 58 sin 58 = 20 / r r = 20 / sin 58 = 23.583568067241928552025478405751 feet ladder must be about (rounding) 23.6 feet long.
23.58 feetA+no its not i just tryed it so yea get your facts right before putting them on herebut i dont even know this so srry for the ppl look for it
1 i think other people feel free to change this
A ladder leaning against a 20ft wall, with an angle of 32 degrees with respect to the wall, must be 24ft long. cos(theta) = adjacent over hypotenuse cos(32) = 20 / hypotenuse hypotenuse = 20 / cos(32) hypotenuse = 23.58
No. since the ladder must be on an angle it must have room so that the length of the ladder is equal to the 282 + (distance between bottom of ladder and house)2.