SecA = 1/CosA
Hence
SecASinA = SinA/CosA = 0
Then SinA = 0
A = 0 , 180, 360
It doesn't matter what the value of CosA is because if CosA = 0 , then the answer is undefined. 44e/.g/
SinA/CosA = SinA / 0 = Undefined.
Use Cosine Rule a^(2) = b^(2) + c^(2) - 2bcCosA Algebrically rearrange CosA = [a^(2) - b^(2) - c^(2)] / -2bc Substitute CosA = [13^(2) - 12^(2) - 5^(2)# / -2(12)(5) CosA = [ 169 - 144 - 25] / -120 Cos)A) = [0] / -120 CosA = 0 A = 90 degrees (the right angle opposite the hypotenuse)/ However, If 'A' is the angle between '12' & '13' then 'a' is the side '5' Hence (Notice the rearrangement of the numerical values). CosA = [5^(2) - 12^(2) - 13^(2) ] / -2(12)(13) CosA = [ 25 - 144 -169] / -312 CosA = [ -288[/-312 CosA = 288/312 A = Cos^(-1) [288/312] A = 22.61986495.... degrees.
The value is 0.
Tan of 0 equals zero.
There aren't. There are three: Sine, Cosine and Tangent, for any given right-angled triangle. They are related of course: for any given angle A, sinA/cosA = tanA; sinA + cosA =1. As you can prove for yourself, the first by a little algebraic manipulation of the basic ratios for a right-angled triangle, the second by looking up the values for any value such that 0 < A < 90. And those three little division sums are the basis for a huge field of mathematics extending far beyond simple triangles into such fields as harmonic analysis, vectors, electricity & electronics, etc.
cotA*cotB*cotC = 1/[tanA+tanB+tanC]
It just means that the value of 0 is equal to the value of 0, which is correct. It's like saying 2 equals 2, or 6 equals 6, or 52657 equals 52657... you get the point.
0. Anything multiplied by 0 equals 0.
If ( x = 0 ) and ( y = 1 ), then ( xy = 0 \times 1 = 0 ). Therefore, the value of ( xy ) is 0.
5s = 0
0 divided by 5 equals 0. 5 divided by 0 equals undefined, not 0.Any number divided by 0 is undefined.
0. The product of any number and 0 is 0.
The correct equation is a^3 - a^2*cos(a) - 6cos(a) = 0 which gives cos(a) = a^3/(a^2 + 6) This is not a simple equation to solve. In any case, before attempting a solution, it is necessary to know whether a is measured in degrees or radians.
here for least value X=2,y=3hence 2(3)-3(2)=0=0
The value of x would be 0
1.2
It is a false statement and therefore has the value 0.
The value is 1 if (x, y) = (4, 3) and 0 otherwise.