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cotA*cotB*cotC = 1/[tanA+tanB+tanC]

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11y ago

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How do you solve right spherical triangle when A is equal to 54 degrees 30' B equals 124 degrees 10' and C equals 90 degrees.Find the sides?

Apply Napier's rulesin co-c= (tanco-A)(tanco-B)cosc= 1/tanAtanBc= cos-1(1/tanAtanB)c=118.96 degreessin a= (cosco-A)(cosco-C)a= sin-1(sinAsinC)a=45.52sinb= (tancoA)(tana)b=sin-1 (tana/tanA)b=46.37 or >>>180-46.37 = 133.63FA= c=118.96 degreesa= 45.52 degreesb= 133.63 degrees


If SecASinA equals 0 then what will be the Value of CosA?

If SecA * SinA equals 0, it implies that either SecA or SinA is equal to 0. Since SecA is the reciprocal of CosA, if SecA is 0, then CosA will be undefined. However, if SinA is 0, then CosA will be either 1 or -1 depending on the quadrant in which angle A lies.


Why are there two sine cosine and tangent ratios?

There aren't. There are three: Sine, Cosine and Tangent, for any given right-angled triangle. They are related of course: for any given angle A, sinA/cosA = tanA; sinA + cosA =1. As you can prove for yourself, the first by a little algebraic manipulation of the basic ratios for a right-angled triangle, the second by looking up the values for any value such that 0 < A < 90. And those three little division sums are the basis for a huge field of mathematics extending far beyond simple triangles into such fields as harmonic analysis, vectors, electricity & electronics, etc.


What is tan20tan32 plus tan32tan38 plus tan38tan20?

Oh honey, you're throwing some trigonometry at me? Alright, buckle up. The sum of tan20tan32 plus tan32tan38 plus tan38tan20 is equal to 1. Just plug in those values and watch the magic happen. Math can be sassy too, you know.