cotA*cotB*cotC = 1/[tanA+tanB+tanC]
Apply Napier's rulesin co-c= (tanco-A)(tanco-B)cosc= 1/tanAtanBc= cos-1(1/tanAtanB)c=118.96 degreessin a= (cosco-A)(cosco-C)a= sin-1(sinAsinC)a=45.52sinb= (tancoA)(tana)b=sin-1 (tana/tanA)b=46.37 or >>>180-46.37 = 133.63FA= c=118.96 degreesa= 45.52 degreesb= 133.63 degrees
secA(sinA)=0 (1/cosA)(sinA)=0 tanA=0 Therefore A is in 1st or 3rd Quadrant i.e A=0 Degrees, 180 Degrees.... This yields cosA=1 or cosA=-1
The area is 99.0 square units.
There are 2 cups in a pint. There are 2 pints in a quart. There are 4 pints in a half gallon, like if you bought a half a gallon if milk at a store. There are 8 pints in a gallon. 10 pints equals 20 cups. 10 pints equals 5 quarts 10 pints equals 2 and a half gallons. 10 pints equals 1 and a quarter gallons. Hope I helped!
It is (tanA+tanB)/{tanA*tanB} - 1/(tanA+tanB)
cotA*cotB*cotC = 1/[tanA+tanB+tanC]
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