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What is the reciprocal of the tangent?
The reciprocal of the tangent is the cotangent, or cot. We might write 1/tan = cot.
The function cot 115 degrees is equivalent to A -tan 65 degrees B -tan 25 degrees C tan 25 degrees D tan 65 degrees?
The cotangent function is the reciprocal of the tangent function, so cot(115 degrees) is equivalent to 1/tan(115 degrees). Since tan(115 degrees) is equivalent to -tan(65 degrees) due to the periodicity of the tangent function, cot(115 degrees) simplifies to -tan(65 degrees), which corresponds to option A.
How can arccot of tanx be simplified?
There is not much that can be done by way of simplification. Suppose arccot(y) = tan(x) then y = cot[tan(x)] = 1/tan(tan(x)) Now cot is NOT the inverse of tan, but its reciprocal. So the expression in the first of above equation cannot be simplified further. Similarly tan[tan(x)] is NOT tan(x)*tan(x) = tan2(x)
How can you verify 1 plus tan theta divided by 1 minus tan theta equals cot theta plus 1 divided by cot theta minus 1?
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
3cot A equals 4 Then find 1-tan?
3cot(A) = 4 so cot(A) = 4/3 then tan(A) = 1/(4/3) = 3/4 and so 1 - tan(A) = 1-3/4 = 1/4
