x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
Not two numbers- the same number twice: 2.5 and 2.5. To find this out, use simultaneous equations: xy=6.25 and x+y=5. Rearrange the second equation to y=5-x and substitute this value for y into the first equation: x(5-x)=6.25. Expand the brackets to get 5x-x2=6.25, subtract 6.25 from both sides to get -x2+5x-6.25=0. Apply the quadratic formula to find the final answer.
Given a complex number z = a + bi, the conjugate z* = a - bi, so z + z*= a + bi + a - bi = 2*a. Note that a and b are both real numbers, and i is the imaginary unit: +sqrt(-1).
Any right angled triangle The Theorem state that the "Sum of the square on the hypotenuse (C) is equal to the sum of the squares on the other two sides (A and B)" That is C2=A2+B2
They equal 180 degrees.
The sum of the first 100 odd numbers is 10,000.
The sum of the first 10 odd whole numbers is 100.
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
The sum is 10,000.
100
100
This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.
It is 100^2=10000
No 5 odd numbers add up to 100. The sum of any two odd numbers is even. The sum of any two even numbers is even. So the sum of any 4 odd numbers must be even. Take that and add an odd number and the sum must be odd. Therefore, the sum of any 5 odd numbers must be odd. 100 is even. In conclusion: The sum of any odd number of odd numbers is odd.
The sum of the first 15 odd numbers is 225.
The sum of the first 300 odd numbers is 90,000
The sum of the first 40 odd numbers is 1,600.