Oh honey, the sum of the first 100 odd numbers is 10,000. You see, the formula for the sum of the first n odd numbers is n^2, and since 100 is the 50th odd number, 50^2 equals 10,000. So, there you have it, darling.
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The sum of the first 100 odd numbers can be calculated using the formula for the sum of an arithmetic series: Sn = n^2, where n is the number of terms. In this case, n = 100, so the sum is 100^2 = 10,000.
Oh, dude, you want me to add up the first 100 odd numbers? That's like asking me to count all the hairs on my head. But hey, I'm feeling generous today. The sum of the first 100 odd numbers is 10,000. So, like, you're welcome for doing all the math for you.
the answer is 2500
I am sorry but this answer is wrong. You only added the numbers between 1 and 100. The question is the first 100 odd numbers, you need to add 1 to 197. The correct answer is 10,000.
x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
Not two numbers- the same number twice: 2.5 and 2.5. To find this out, use simultaneous equations: xy=6.25 and x+y=5. Rearrange the second equation to y=5-x and substitute this value for y into the first equation: x(5-x)=6.25. Expand the brackets to get 5x-x2=6.25, subtract 6.25 from both sides to get -x2+5x-6.25=0. Apply the quadratic formula to find the final answer.
Given a complex number z = a + bi, the conjugate z* = a - bi, so z + z*= a + bi + a - bi = 2*a. Note that a and b are both real numbers, and i is the imaginary unit: +sqrt(-1).
Any right angled triangle The Theorem state that the "Sum of the square on the hypotenuse (C) is equal to the sum of the squares on the other two sides (A and B)" That is C2=A2+B2
They equal 180 degrees.