Oh honey, the sum of the first 100 odd numbers is 10,000. You see, the formula for the sum of the first n odd numbers is n^2, and since 100 is the 50th odd number, 50^2 equals 10,000. So, there you have it, darling.
x + y = 28 x*y = 7 x=7/y replacing X in eq 1 7/y+y=28 y^2 - 28y + 7 = 0 using above solutions find the reciprocal and sum -- Dhruv
Given a complex number z = a + bi, the conjugate z* = a - bi, so z + z*= a + bi + a - bi = 2*a. Note that a and b are both real numbers, and i is the imaginary unit: +sqrt(-1).
Not two numbers- the same number twice: 2.5 and 2.5. To find this out, use simultaneous equations: xy=6.25 and x+y=5. Rearrange the second equation to y=5-x and substitute this value for y into the first equation: x(5-x)=6.25. Expand the brackets to get 5x-x2=6.25, subtract 6.25 from both sides to get -x2+5x-6.25=0. Apply the quadratic formula to find the final answer.
Any right angled triangle The Theorem state that the "Sum of the square on the hypotenuse (C) is equal to the sum of the squares on the other two sides (A and B)" That is C2=A2+B2
They equal 180 degrees.
The sum of the first 100 odd numbers is 10,000.
The sum of the first 10 odd whole numbers is 100.
The sum of the first 100 odd numbers (1 through 199) is 10000 (ten thou)
The sum is 10,000.
100
100
This is very easy. Simply square the number: 100 squared (100 x 100) = 10,000. So, the sum of the first 100 odd numbers is 10,000.
It is 100^2=10000
The sum of the first 300 odd numbers is 90,000
The sum of the first 1,000 odd numbers is 1,000,000.
The sum of the first 40 odd numbers is 1,600.
The sum of the first 50 odd numbers is 2,500.