Given a complex number z = a + bi, the conjugate z* = a - bi, so z + z*= a + bi + a - bi = 2*a. Note that a and b are both real numbers, and i is the imaginary unit: +sqrt(-1).
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A triangle is a closed shape with 3 straight lines, where the sum of its angles is 180 degrees.
i34 is the complex part of the number 0+i34. The real part is 0, so this is a purely imaginary number.
It is 3/13 - 2/13*i
ax2 + bx + c = 0 , find the value of x . b2-4ac>o x is real (2 different values will solve) b2-4ac=o -> a double root (a single real number will solve it) x=real numbers. b2-4ac<0 x= two complex number roots (either pure imaginary or a complex number with real and imaginary components)
Oh honey, the sum of the first 100 odd numbers is 10,000. You see, the formula for the sum of the first n odd numbers is n^2, and since 100 is the 50th odd number, 50^2 equals 10,000. So, there you have it, darling.