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In a triangle ABC b equals 15 cm and c equals 25 cm and also angle B equals 32'15'Find the side a and other angles?
By the sine rule, sin(C)/c = sin(B)/b so sin(C) = 25/15*sin(32d15m) = 0.8894 so C = 62.8 deg or 117.2 deg. Therefore, A = 180 - (B+C) = 85.0 deg or 30.5 deg and then, using the sine rule again, a/sin(A) = b/sin(B) so a = sin(A)*b/sin(B) = 28 or a = 14.3
Diameter of a ball that is 8cm deep and 24cm wide?
The width of a ball is its diameter, so the diameter of a ball that is 24 cm wide is 24 cm.
Volume of triangular prism?
I think first you calculate the area of the triangular face. If you forgot that's ok. The formula is A= bxh divided by 2 which is the same as the area of a triangle is base multiplyed by height and divided by two. Then you need to know the length of the prism(the length of the rectangle)and multiply them together. So your calculation should look like this: Triangular face- A=bxh divided by 2 let's say that the base of the triangle is 5 cm and the height is 12cm Length of prism- let's say the length is 25 cm A=bxh divided by 2 A=5 x 12 divided by 2 A = 20 divided by 2 A = 30 cm squared 30 x 25 = 750cm squared( little 2)
What is the area of an octagon with a side length of 6 cm?
An octagon is a square with the four corners removed. These four corners are right angles triangles, with a hypotenuse of of 6 cm. So we need to find the area of these four triangles and remove(subtract) from a larger square. Using ~Pythagoras. 6^(2) = a^(2) + a^(2) Hence 36 = 2a^(2) 18 = a^(2) a = 3sqrt(2) The side length of the triangles. So the area of these triangles is 4 x 0.5 x 3sqrt(2) x 3sqrt(2( = 36 cm^(2) Now the side length of a large square enclosing the octagon. is 6 + 3sqrt(2) + 3sqrt(2( = 6 + 6sqrt(2) The overall area of the 'large square; is ( 6 + 6sqrt(2))^(2) = )Use FOIL). (6 + 6sqrt(2))(6 + 6sqrt(2)) = 36 + 36sqrt(2) + 36 sqrt(2)+ 72) = 108 + 72sqrt(2) cm^(2) So subtract from the area , the four corner area which is from above 36cm^(2) Hence 108 + 72sqrt(2) - 36 = (72 + 72sqrt(2() cm^(2) or 72(1 + sqrt(2)) cm^(2) or 173.8233765 ... cm^(2).
In triangle ABC with right angle at C if a equals 10 cm and angle B equals 59 degrees then c equals 11.67 cm Rounded-off to two decimals?
Absolutely not!If C is the right angle, then by conventional notation, c is the hypotenuse and so is the longest side!
