An octagon is a square with the four corners removed.
These four corners are right angles triangles, with a hypotenuse of of 6 cm. So we need to find the area of these four triangles and remove(subtract) from a larger square.
Using ~Pythagoras.
6^(2) = a^(2) + a^(2)
Hence
36 = 2a^(2)
18 = a^(2)
a = 3sqrt(2) The side length of the triangles.
So the area of these triangles is 4 x 0.5 x 3sqrt(2) x 3sqrt(2( = 36 cm^(2)
Now the side length of a large square enclosing the octagon. is
6 + 3sqrt(2) + 3sqrt(2( = 6 + 6sqrt(2)
The overall area of the 'large square; is ( 6 + 6sqrt(2))^(2) = )Use FOIL).
(6 + 6sqrt(2))(6 + 6sqrt(2)) =
36 + 36sqrt(2) + 36 sqrt(2)+ 72) = 108 + 72sqrt(2) cm^(2)
So subtract from the area , the four corner area which is from above 36cm^(2)
Hence
108 + 72sqrt(2) - 36 = (72 + 72sqrt(2() cm^(2) or
72(1 + sqrt(2)) cm^(2)
or
173.8233765 ... cm^(2).
I think first you calculate the area of the triangular face. If you forgot that's ok. The formula is A= bxh divided by 2 which is the same as the area of a triangle is base multiplyed by height and divided by two. Then you need to know the length of the prism(the length of the rectangle)and multiply them together. So your calculation should look like this: Triangular face- A=bxh divided by 2 let's say that the base of the triangle is 5 cm and the height is 12cm Length of prism- let's say the length is 25 cm A=bxh divided by 2 A=5 x 12 divided by 2 A = 20 divided by 2 A = 30 cm squared 30 x 25 = 750cm squared( little 2)
Absolutely not!If C is the right angle, then by conventional notation, c is the hypotenuse and so is the longest side!
This answer uses trigonometry to avoid a lot of work:tangent = opposite/adjacent and tangent*adjacent (base of ladder from the building) = opposite (height of ladder above ground)So: tangent 60 degrees*3 = 5.196152423Therefore: Top of the ladder above ground = 5.2 meters correct to one decimal place.More laborious methodThe right triangle formed by the wall, ground and ladder has sides in the ratio of 1::2::sq-rt-of-3. The shortest side is the one opposite the 30 degree angle, i.e., the given distance from wall to base of the ladder--3 m.The length of the ladder represents the hypotenuse of the triangle, and is twice as long, hence 6 m.And the height of the ladder's top from the ground is proportional to the third side whose length is sq-rt-3 times that of the shortest side. Sq-rt-3 is about 1.732, so height of the ladder's top at the wall is about 5.20 m, or 520 cm.
The width of a ball is its diameter, so the diameter of a ball that is 24 cm wide is 24 cm.
The volume is 14,137.2 cm3
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
An octagon with a side length of 5.8 cm has an apothem that is approximately 7 cm. The area of such a shape is approx 162.4 sq cm.
perimeter of octagon is 128 cm= 8 * side side of the octagon=128/8=16 cm
A regular octagon is a polygon with 8 sides of equal length. To find the area of a regular octagon with a side length of 24 cm, we can use the following formula: Area = (8 × side^2) / (4 × tan(π/8)) where side = 24 cm Plugging in the value, we get: Area = (8 × 24^2) / (4 × tan(π/8)) Area ≈ 736.44 cm^2 So, the area of the regular octagon is approximately 736.44 square centimeters.
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s (apothem times one-half the perimeter)So for this example, (7 cm and 8.45 cm) Area = (8.45)(28) = 236.6 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 7 cm , the area is also about 236.6 cm2.(This formula is generated by adding or subtracting the missing corner triangles.)
By Apothem LengthThe area of a regular octagon can also be computed using its measured apothem (a line from the center to the middle of any side). The formula for an octagon with side length s and apothem a is Area = a4s . (apothem times one-half the perimeter)So for this example, (8 cm and 9.66 cm) Area = (9.66)(32) = 309.12 cm2----By Side LengthThe area of a regular octagon with side length s is given as Area = 4.828427 s2 , so for a regular octagon of side length 8 cm , the area is calculated as 309.02 cm2. (indicating an error from rounding the apothem length)(This formula is generated by adding or subtracting the missing corner triangles.)
Length + width = 18 cm so length = 12 cm and width = 6 cm. Presumably the length is the common side so the perimeter of the octagon is 8 x 12 = 96 cm. If the width is the common side then the perimeter of the octagon is 8 x 6 = 48 cm
64 cm
An octagon has eight sides, in this case all the same length. Total length of eight sides = 40 cm. Length of each side = 40 divided by 8 equals 5 cm
Octagon is equal in area to 8 rectangles, length 9.3, width 7.7/2 ie 3.75. Area of each of these is 35.805 sq cm so total area is 286.44 sq cm. Alternatively you can mutiply the square of the apothegm by 3.314 (8/tan 67.5) which gives 286.6.
It is 72 cm/8 = 9 cm.
If a regular octagon has a perimeter of 40cm, then each side is 5 cm.