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What is the area of a rhombus when one side and a diagnol is given?
Wiki User
∙ 15y ago
A rhombus has 4 congruent sides, its diagonals bisect each other and are perpendicular between them.
If we know the length of the side, a, and the length of one of the diagonals, d1, we can find the area, A, of the rhombus which is:
A = (d1)[(1/2)(d2)]
How to find the one half of d2?
(1/2)(d2) = √[a^2 - [(1/2)(d1)]^2] = √[a^2 - (1/4)(d1)^2]
So,
A = (d1)[(1/2)(d2)]
A = (d1)√[a^2 - (1/4)(d1)^2]
A = √[(d1^2)[a^2 - (1/4)(d1)^2]]
A = √[(d1^2)(a^2) - (d1^4)/4]
Wiki User
∙ 15y ago
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The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).The area of a rhombus cannot be determined form its side lengths. The shape can be flexed into a square (when it has maximum area) to a long thin rhombus (when it has minimum area).
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