That will depend on the length of the other diagonal because area of a rhombus is 0.5*product of its diagonals.
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²
Do exactly the same thing for a rhombus or a parallelogram A = base x height (parallelogram) OR A = 1/2 x diagonal 1 x diagonal 2
If those are its diagonals then area is: 0.5*10*11 = 55 square units other wise use Pythagoras to find diagonal EG because area of a rhombus is 0.5 times the product of its diagonals.
A diagonal is a line so the area of any diagonal must be zero.
Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 36) = 6√2 ≈ 8.49
That is one of the ways of finding the area of a rhombus. The area is half the product of the diagonals. In this case, 1/2 of 7 x 4.4 or .154. You can also find the area of a rhombus by using one side as the base and finding an altitude for that base and multiplying them. There is a third way using trigonometry.
it is impossible for a diagonal of a rhombus to be the same length as its perimeter
Diagonals of a rhombus are perpendicular so the product is the area. If x is the smaller diagonal, the longer is 4x, and the area if 4x2.
63
310
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
Given: The area of the rhombus is 120 square feet The diagonal of the rhombus is 16 feet think of the rhombus being two identical triangles, connected at their base which is 16 feet long. Each of them would then have an area of 60 feet. Now, in a triangle, area = (base * height) / 2 the area is already given as 60, and the base as 16 we can say then: 60 = (16 * h) / 2 ∴60 = 8h ∴h = 7.5 Now, that 7.5 is half the length of the rhombus (as it's the height of one of our triangles, which each are half our rhombus). So we know that that the other diagonal on the rhombus is twice that. In other words, the answer is 15.
231 Radical 3
it VARIES! --- 10by10by10by10=25sqrt3
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²
The diagonals bisect each other. Since that is true then the area of the rhombus is the sum of the two triangles. Half of one diagonal times the other diagonal.2(6x5)/2 or 6x5=30
Area of Rhombus = length of first diagonal x length of second diagonal / 2 / means divided by So for your problem: Area of Rhombus = 10 feet x 14 feet / 2 = 70 square feet