24
128
555
Six.
8x7x6x5x4= 6720
All I know is that each person can sit on a chair. There aren't many ways with the details you said. There might be 2 chairs with 2 people on each chair. There really only is one way.
5 chairs x 5 people = 25 choices
12
NO
It is 2*4! = 2*24 = 48
If the first woman sits at an end, there is only the seat next to her where the second woman can sit. There are 2 such chairs, giving 2 × 1 = 2 possible sittings. If the first woman doesn't sit at the end, the second woman can sit either side of her in one of 2 chairs. There are 5 - 2 = 3 such chairs, giving, 2 × 3 = 6 possible sittings. Thus there are 2 + 6 = 8 possible sitting positions of the women. For each of these there are 3 empty chairs which the man can occupy, Thus there are 8 × 3 = 24 possible ways that 2 women and 1 man can sit on a row of 5 empty chairs if the two women must sit together.
8 chairs