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A number is divisible by 3 if the sum of its digits is divisible by 3.
You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.
Let's assume, or hope, that the blank is after those numbers. 67_ and 45_ For a number to be divisible by three, the total of the number's digits has to be divisible by three. 672 and 450
2, 5 or 8.
If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.
blank = 2 is a possible answer.
shut up and do something better with your life
2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3
blank = representation.
remainder
10,180 is not divisible by six.
A number is divisible by another when the remainder after division by that number is zero.