C = 5
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
This does not sound like an equation. This sounds like evaluating an algebraic expression. 3C means 3 times the value of C (which you have given as 21) then subtract 15. 3 x 21 - 15 = 48
6
The value of 'c' that makes the equation a true statement is the answer.Here's how to find it:Write the equation:3c - 15 = 17 - cAdd 'c' to each side:4c - 15 = 17Add 15 to each side:4c = 32Divide each side by 4:c = 8
2c-10
15
Yes because A > B, B > C, so A has to be > C.ExampleA=5B=3C=1A (5) > B (3)B (3) > C (1)A (5) > C (1)
C = 5
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
This does not sound like an equation. This sounds like evaluating an algebraic expression. 3C means 3 times the value of C (which you have given as 21) then subtract 15. 3 x 21 - 15 = 48
6
It is:- 3c+5 = c+15 Subtact 5 and c from both sides: 2c = 10 Divide both sides by 2 to find the value of c: c = 5
The value of 'c' that makes the equation a true statement is the answer.Here's how to find it:Write the equation:3c - 15 = 17 - cAdd 'c' to each side:4c - 15 = 17Add 15 to each side:4c = 32Divide each side by 4:c = 8
3c+5
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
3c-7 = -4