C = 5
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
This does not sound like an equation. This sounds like evaluating an algebraic expression. 3C means 3 times the value of C (which you have given as 21) then subtract 15. 3 x 21 - 15 = 48
6
The value of 'c' that makes the equation a true statement is the answer.Here's how to find it:Write the equation:3c - 15 = 17 - cAdd 'c' to each side:4c - 15 = 17Add 15 to each side:4c = 32Divide each side by 4:c = 8
2c-10
Oh, dude, you're hitting me with some math lingo! So, like, the factor of 3c would just be 3, because it's the number that divides evenly into 3c. It's like the cool friend that 3c can always rely on to hang out with.
Yes because A > B, B > C, so A has to be > C.ExampleA=5B=3C=1A (5) > B (3)B (3) > C (1)A (5) > C (1)
C = 5
(3c +15)/(c2 - 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + c/(c + 5)= (3c + 15)/(c - 5)(c + 5) + [c(c - 5)/(c + 5)(c - 5)(since the common denominator is (c + 5)(c - 5)= (3c + 15)/(c - 5)(c + 5) + (c2 - 5c)/(c + 5)(c - 5)= (3c + 15 + c2 - 5c)/(c - 5)(c + 5)= (c2 - 2c + 15)/(c - 5)(c + 5)= [(c - 5)(c + 3)]/(c - 5)(c + 5) (simplify)= (c + 3)/(c + 5)
This does not sound like an equation. This sounds like evaluating an algebraic expression. 3C means 3 times the value of C (which you have given as 21) then subtract 15. 3 x 21 - 15 = 48
6
It is:- 3c+5 = c+15 Subtact 5 and c from both sides: 2c = 10 Divide both sides by 2 to find the value of c: c = 5
The value of 'c' that makes the equation a true statement is the answer.Here's how to find it:Write the equation:3c - 15 = 17 - cAdd 'c' to each side:4c - 15 = 17Add 15 to each side:4c = 32Divide each side by 4:c = 8
3c+5
3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4
3c-7 = -4