12 dozens in a carton?
The answer might depend on what c and d are supposed to be!
As A/B=C/D , So B=(A*D)/C
the answer is a
C = D C = 10 utils, and D = 10 utils
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
7=dd=3 so 7 goes by 3+d = cC=cost and so it equals 10+1902 =1912
12=n in a d
c = 6 and d = 7
If: a = b+c+d Then: c = a-b-d
There are four unknown variables and only three linear equations so there is not a unique solution. All you can do is to rearrange the four variables so that three of them can be expressed in terms of the fourth. For example: In terms of c, a = 6 - c/2 b = a - c = 6 - 3c/2 d = c
6d = c Divide both sides by 6: d = c/d
The value of c/30 that equals 12 is 12 . In order to make that value, 'c' must be 360 .
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
P = Pieces/PartsD = Dozen
If we're talking strictly algebra. 12 equals p of c can be written as: 12= p(c) meaning, 12 is the answer for some function p, when c is the variable.
15= M on a D M C
The product of the means equals the product of the extremes. In other words, if A is to B as C is to D, then B times C equals A times D, so... A = B x C Ã· D B = A x D Ã· C C = A x D Ã· B D = B x C Ã· A
ASSs a. c. 8 b. 7 d. 12
5 and a half