12 dozens in a carton?
The answer might depend on what c and d are supposed to be!
c = 6 and d = 7
If a=b and c=d then (a+c)=(b+d) ? This is proved very simply by the direct application of perhaps the most fundamental statement in all of Algebra: "If equals are added to equals, the sums are equal."
If we're talking strictly algebra. 12 equals p of c can be written as: 12= p(c) meaning, 12 is the answer for some function p, when c is the variable.
12 dozens in a carton?
The answer might depend on what c and d are supposed to be!
the answer is a
C = D C = 10 utils, and D = 10 utils
They all equal each other. a = b = c = d = e e = a e = b e = c e = d e = e
As A/B=C/D , So B=(A*D)/C
c = 6 and d = 7
There are four unknown variables and only three linear equations so there is not a unique solution. All you can do is to rearrange the four variables so that three of them can be expressed in terms of the fourth. For example: In terms of c, a = 6 - c/2 b = a - c = 6 - 3c/2 d = c
12=n in a d
ASSs a. c. 8 b. 7 d. 12
If: a = b+c+d Then: c = a-b-d
c