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Q: 2 times the sum of h and 3?

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It is: 9h+4(2+h) = 9h+8+4h => 13h+8

Its height (h) is side (s) times sin 60 orsqrt(3)/2 times side = .866s h = .866s s = h/.866 = 2/sqrt(3) s = 1.154 h perimeter = s + s + s = 3s = 3 x 2/sqrt(3) = 3.46s

Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)

This is a nice bit of calculus. You sum up an infinite number of infinitely thin slices of the cone as follows: Radius of each slice = r*(h-x)/h Surface area of each slice = Pi*r2(h-x)2/h2 Integral of Pi*r2(h-x)2/h2 dx evaluated from 0 to h = Pi*r2*h/3

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Related questions

It is: 9h+4(2+h) = 9h+8+4h => 13h+8

6h

It means that you multiply 2 by any given number (h) and then multiply by 5. h is the variable. A variable is anunknown number. So if h is 3, then you replace it with h so 2 times 3 is 6 times 5 is 30.

Its height (h) is side (s) times sin 60 orsqrt(3)/2 times side = .866s h = .866s s = h/.866 = 2/sqrt(3) s = 1.154 h perimeter = s + s + s = 3s = 3 x 2/sqrt(3) = 3.46s

in singles match between each other 4-3 to triple h and in tag team matches 2-2 or tie

Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)

This is a nice bit of calculus. You sum up an infinite number of infinitely thin slices of the cone as follows: Radius of each slice = r*(h-x)/h Surface area of each slice = Pi*r2(h-x)2/h2 Integral of Pi*r2(h-x)2/h2 dx evaluated from 0 to h = Pi*r2*h/3

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3/10*h or 0.3*h

Its sum is: 1/2+1/2 = 1

3+h

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