6h
2(h + 3) = 2h + 6
It means that you multiply 2 by any given number (h) and then multiply by 5. h is the variable. A variable is anunknown number. So if h is 3, then you replace it with h so 2 times 3 is 6 times 5 is 30.
Its height (h) is side (s) times sin 60 orsqrt(3)/2 times side = .866s h = .866s s = h/.866 = 2/sqrt(3) s = 1.154 h perimeter = s + s + s = 3s = 3 x 2/sqrt(3) = 3.46s
in singles match between each other 4-3 to triple h and in tag team matches 2-2 or tie
Apply Pythagoras h^(2) = x^(2) + y(2) Hence for points ( -8,-3 ) & ( 4,5) h^(2) = (-8-4)^(2) + ( -3-5)^(2). h^(2) = (-12)^(2) + (-8)^(2) h^(2) = 144 + 64 h^(2) = 208 h = sqrt(208) h = 14.222051.... (The distance between the two points.
3/10*h or 0.3*h
3+h
-1
Possibilities on the first toss = 2. For each of these . . . Possibilities on the second toss = 2. Fo reach of these . . . Possibilities on the third toss = 2. Total possible sequances in 3 tosses = 2 x 2 x 2 = 8. Number of ways to get heads exactly twice = 3 . H - H - T H - T - H T - H - H Probability of exactly 2 heads in 3 tosses = 3/8 = 37.5% . Odds = 3 in 8, or 5 to 3 against it.
3 divide h
There are 16 possible outcomes, each of which is equally likely. So each has a probability of 1/16 HHHH: X = H*T = 4*0 = 0 HHHT: X = H*T = 3*1 = 3 HHTH: X = H*T = 3*1 = 3 HTHH: X = H*T = 3*1 = 3 THHH: X = H*T = 3*1 = 3 HHTT: X = H*T = 2*2 = 4 HTHT: X = H*T = 2*2 = 4 HTTH: X = H*T = 2*2 = 4 THHT: X = H*T = 2*2 = 4 THTH: X = H*T = 2*2 = 4 TTHH: X = H*T = 2*2 = 4 HTTT: X = H*T = 1*3 = 3 THTT: X = H*T = 1*3 = 3 TTHT: X = H*T = 1*3 = 3 TTTH: X = H*T = 1*3 = 3 TTTT: X = H*T = 0*4 = 0 So, the probability distribution function of X is f(X = 0) = 1/16 f(X = 1) = 4/16 = 1/4 f(X = 2) = 6/16 = 3/8 f(X = 3) = 4/16 = 1/4 f(X = 4 = 1/16 and f(X = x) = 0 for all other x
b times h times 1/2 or b times h divide by 2