2(h + 3) = 2h + 6
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It is: 9h+4(2+h) = 9h+8+4h => 13h+8
Its height (h) is side (s) times sin 60 orsqrt(3)/2 times side = .866s h = .866s s = h/.866 = 2/sqrt(3) s = 1.154 h perimeter = s + s + s = 3s = 3 x 2/sqrt(3) = 3.46s
Which of the following formulas is used to find the area of a trapezoid? Solution: 1/2 h(B+b) The area of a trapezoid is 1/2 times the height times the sum of both bases. h is the height, b is the top base and B is the bottom base. A trapezoid=1/2×h×(B+b)
This is a nice bit of calculus. You sum up an infinite number of infinitely thin slices of the cone as follows: Radius of each slice = r*(h-x)/h Surface area of each slice = Pi*r2(h-x)2/h2 Integral of Pi*r2(h-x)2/h2 dx evaluated from 0 to h = Pi*r2*h/3
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