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There are two simultaneous equations, so to solve for y, eliminate x:

1) 2x + 3y = 3

2) 4x - 3y = 9

Multiply equation (1) by 2 giving:

1) 4x + 6y = 6

2) 4x - 3y = 9

Next, subtract equation (2) from equation (1), giving:

(4x - 4x) + (6y - -3y) = 6 - 9

→ 9y = -3

→ y = -1/3

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Q: 2x plus 3y equals 3 and 4x minus 3y equals 9. What value of y is part of the solution for this system of equations?
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