This is like not words
the (n-1)th term plus the (n-2)th term.
The (n)th term = the (n - 1)th term + (2n + 1)
If you have this series: 1,2,3,4,5,6,7,8The 8th term is 8 and the n-th term is n.But if you have this series: 2,4,6,8,10,12,14,16The 8th term is 16 and the n-th term is 2n
The Nth term formula for oblong numbers is N = N(N+1)
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term for any A.P, n-th term is a(n)=a(1)+ (n-1)d where a(1)=first term and d=common difference here a(1)=100, and d= -11 so, a(n)=100+(n-1)x(-11) or, a(n)=111-11n
The nth term IS 4n + 3 ie 4 times n and then add 3.
10 - 52 = -15
The r+1 th term is nCr(-x)r where r = 0, 1, 2, ... , n. and where nCr = n!/[r!*(n-r)!]
n = 100 + 7 = 107