This is like not words
the (n-1)th term plus the (n-2)th term.
If you have this series: 1,2,3,4,5,6,7,8The 8th term is 8 and the n-th term is n.But if you have this series: 2,4,6,8,10,12,14,16The 8th term is 16 and the n-th term is 2n
The Nth term formula for oblong numbers is N = N(N+1)
Use the following formula: an = a1 + (n - 1)d, where a1 = the first term n = the n th term (general term) d = common difference (which is constant between terms) Since we need to find the 14 th term, we can write: a1 = 100 n = 14 d = -4 an = a1 + (n - 1)d a14 = 100 + (14 - 1)(-4) a14 = 100 + (13)(-4) a14 = 100 - 52 a14 = 48 Thus, the 14 th term is 48.
Let n (i) = the term number of each term in the sequence., with (i) going from 1-6 E.g term number 1 (n (1) ) is 3. n(2)= -7 etc... Therefore n(i) for odd terms in the sequence is n (i)= (n (i -2)th term +1). For even terms in the sequence, n(i)= (n (i - 2)th term -3).
This is the Fibonacci sequence, where the number is the sum of the two preceding numbers. The nth term is the (n-1)th term added to (n-2)th term
clearly the given series is an arithmetic progression with a common difference of -11,that is every term is obtained by subtracting 11 from the previous term for any A.P, n-th term is a(n)=a(1)+ (n-1)d where a(1)=first term and d=common difference here a(1)=100, and d= -11 so, a(n)=100+(n-1)x(-11) or, a(n)=111-11n
The nth term IS 4n + 3 ie 4 times n and then add 3.
10 - 52 = -15
To find the nth term in this sequence, we first need to determine the pattern. The differences between consecutive terms are 5, 7, 9, and 11 respectively. These differences are increasing by 2 each time. This indicates that the sequence is following a quadratic pattern. The nth term for this sequence can be found using the formula for the nth term of a quadratic sequence, which is Tn = an^2 + bn + c.
The formula for the sum of the first n terms of an arithmetic progression is Sn = n/2 * (a + l), where Sn is the sum, n is the number of terms, a is the first term, and l is the last term.
The r+1 th term is nCr(-x)r where r = 0, 1, 2, ... , n. and where nCr = n!/[r!*(n-r)!]