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A number is divisible by another when the remainder after division by that number is zero.

Q: A number is divisible by another when the BLANK after division by that number is 0?

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Let's assume, or hope, that the blank is after those numbers. 67_ and 45_ For a number to be divisible by three, the total of the number's digits has to be divisible by three. 672 and 450

2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3

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If the number is divisible by 9 the sum of its digits (its digital root) must be divisible by 9. 5+6+8+9 = 28 The next multiple of 9 is 36 and that is 8 more. So the missing digit must be 8.

(1) equiangular, (2) division

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Its the remainder

remainder

the answer would be 10 * * * * * hi hi hi hi hi hi hi i am from india and will atempt to scam you I suspect that this is a "fill in the blank" question and the blank should appear between "the" and "after" and the word in that blank should be "remainder". ****** My 5th grader got the same question. You are right it is a fill in question! The question should read: A number is divisible by another number when the __________________ after division by that number is 0. It seems to make more sense if they wrote it as follows: A number is divisible by another number if after dividing the remainder is zero.

yes, this just says that there is a 0 remainder. For example, 6 is divisible by 3 since the remainder is 0

blank = 2 is a possible answer.

A number is divisible by 3 if the sum of its digits is divisible by 3.

Let's assume, or hope, that the blank is after those numbers. 67_ and 45_ For a number to be divisible by three, the total of the number's digits has to be divisible by three. 672 and 450

You would fill in the blank with the word sum, which means that you add each of the digits of the number. If that sum is divisible by three then the number is divisible by 3.

2. To test a number to be divisible by 3, add up the digits and if the sum is divisible by 3, so is the original number. If not, the excess over a multiple of 3 gives the remainder when the original number is divided by 3. Subtract this remainder from 3 and this gives the smallest digit to replace the blank; unless the remainder is 0, in which case the blank can be replaced by a 0: 8 + 6 + 9 + 3 + 5 = 31 → 31 ÷ 3 = 10 remainder 1 Replace blank by 3 - 1 = 2: 826935 is divisible by 3

shut up and do something better with your life

11

10,180 is not divisible by six.