The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
Diagonal = 10 meters.
If the diagonal is 25m and the area is 168m2 then the longest edge of the rectangle will be 24m.
30 ft
Width is 5.
About 12.7. (I got it from using the pythagreon theyrom.)
15 cm for the diagonal.
The answer depends on what information you have about the rectangle: the area and width, or width and diagonal, area and perimeter or some other measures.
64 centimetres.
The diagonal is 7.21 feet.
Using Pythagoras' theorem it works out as 194.9820505 or 195 centimeters
To find the length of a diagonal in a rectangle, use the Pythagorean method. Diagonal length = square root(length squared + height squared).
The length of the diagonal is about 16.03 feet.
-- A rectangle has no 'formula'. -- The length of the diagonal is 24feet 10.62inches (rounded)
The diagonal is 26cm
Diagonal = 17 cm and height = 8 cm so Length = sqrt[172 - 82] = sqrt(225) = 15 cm Then area = length*height = 15*8 = 120 cm2
The diagonal length is about 18.44 inches.
This length (diagonal) = sq.rt ( l2 + b2 ) where 'l' is length of the rectangle and 'b' is the breadth of the rectangle.