To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. In this case, the diagonal forms the hypotenuse of a right triangle with the sides being the length and width of the rectangle. So, the diagonal (d) can be calculated as d = √(4^2 + 6^2) = √(16 + 36) = √52 ≈ 7.21 feet.
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
60.28 is the length of the diagonal, got through Pythagoras' Theorem.
(Diagonal)2 = (36)2 + (26)2 = 1,972Diagonal = sqrt(1,972) = 44.4072 (rounded)
46.648 ft
Oh, dude, you're hitting me with the math questions now? Okay, okay, so if you wanna find the diagonal of an 8 ft by 12 ft rectangle, you can use the Pythagorean theorem. It's like a^2 + b^2 = c^2, so in this case, 8^2 + 12^2 = c^2. Just crunch those numbers and you'll get the diagonal length. Easy peasy, right?
18.9 feet
18.9 feet
The area of the rectangle is the product of the length of the sides (provided the units of length are the same). Imagine a rectangle 6ft long and 10ft wide. You could even draw it if it helps. 6 multiplied by 10 is 60, so the area of a 6ft*10ft rectangle is 60ft2 or 60 sq. ft.
(Diagonal)2 = (15)2 + (8)2 = (225) + (64) = 289Diagonal = sqrt(289) = 17
To find the length of the diagonal of a rectangle, you can use the Pythagorean theorem. For a rectangle with length ( l = 36 ) ft and width ( w = 18 ) ft, the diagonal ( d ) can be calculated using the formula ( d = \sqrt{l^2 + w^2} ). Plugging in the values, ( d = \sqrt{36^2 + 18^2} = \sqrt{1296 + 324} = \sqrt{1620} ). This simplifies to ( d \approx 40.31 ) ft.
To find the length of the diagonal of a rectangle, we can use the Pythagorean theorem, which states that the square of the length of the diagonal is equal to the sum of the squares of the lengths of the two sides. In this case, the diagonal length (d) can be calculated as follows: d^2 = 30^2 + 50^2. Therefore, d^2 = 900 + 2500 = 3400. Taking the square root of 3400 gives us the diagonal length, which is approximately 58.3 feet.
A rectangle = LW If the diagonal of length of 10 ft makes a 55⁰ angle with length L, then the length of width W equals to 10 sin 55⁰ ft, and the length of L equals to 10 cos 55⁰ ft. So that A = LW = (10 sin 55⁰ ft)(10 cos 55⁰ ft) ≈ 47 ft2
114.826 ft
120 feet
The length of the diagonal is 208.7*sqrt(2) = 295.1 ft.
20 ft
43.26661530556787