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What is the diagonal length of a rectangle with the sides of 10 and 8?
Wiki User
∙ 14y ago
About 12.7. (I got it from using the pythagreon theyrom.)
Wiki User
∙ 14y ago
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What is the length of a diagonal of a rectangle with a length of 8 meters and width of 6 meters?
Diagonal = 10 meters.
A rectangle has a diagonal that measures 10 centimeters and a length that is 2 centimeters longer than the width What is the width of the rectangle in centimeters?
The simplest Pythagorean triangle is 3, 4 and 5. Double this gives 6, 8 and 10 so the sides of your rectangle are 6 cm & 8 cm.
What is the length and the width of a rectangle with a perimeter of 36 units?
A rectangle with a perimeter of 36 units can have sides of any length as long as the lengths of the two differently-sized sides are equal to 18. For example, a rectangle with sides of 10 units and 8 units (don't forget to state what these units are, whether they are inches or centimetres or any other similar measurement), would have a perimeter of 36.
A rectangle has perimeter of 20m Express the area of the rectangle as a function of the length of one of its sides?
In a rectangle: P = 2(L + W) and A = LW P = 2(L + W) (replace P with 20) 20 = 2(L + W) (solve for L; divide by 2 to both sides) 10 = L + W (subtract W to both sides ) 10 - W = L A = LW (substitute 10 - W for L) A = (10 - W)W A = 10W - W2
What is the formula of square whose one sides is 10 mm?
The formula for what? Its perimeter, area, diagonal, etc.
What is the length of a diagonal of a rectangle with a length of 8 meters and width of 6 meters?
Diagonal = 10 meters.
What is the length of the diagonal of a rectangle that has a length of 16 ft and width of 10 ft?
Diagonal = 18.867 feet.
What is the area of a rectangle with a side of8 and diagonal of 10?
Area = length x width. You have one of the sides; to get the other side, use the Pythagorean Theorem. Then multiply the two sides.
The width of a rectangle is 10 meters and its area is 120 square meters What is the length of the diagonal?
The diagonal is 15.620 meters.
What is the diagonal of the rectangle has length 6 and width 8?
The diagonal = the square root of (6 squared + 8 squared) 6 squared+8squared = 100 the square root of 100 = 10 so the length of the diagonal is 10. The above used Pythagoras' theorem which says the square on the diagonal is equal to the sum of the squares on the other two sides.
Find the length of the diagonal of a rectangle that has a length of 16 ft and width of 10 ft?
18.9 feet
Find the length of the diagonal of a rectangle that has a length of 16 ft. and width of 10 ft.?
18.9 feet
Find the area of a rectangle whose diagonal is 10 feet long and makes a 55 degree angle with one of the sides?
A rectangle = LW If the diagonal of length of 10 ft makes a 55⁰ angle with length L, then the length of width W equals to 10 sin 55⁰ ft, and the length of L equals to 10 cos 55⁰ ft. So that A = LW = (10 sin 55⁰ ft)(10 cos 55⁰ ft) ≈ 47 ft2
A rectangle has a diagonal of 10 and a length of 8. what is its width?
Using Pythagoras' theorem its width is 6 units in length.
How long is the diagonal of a rectangle with dimensions 7in by 10in?
You use the pythagorous theorm to calculate the hypotenuse of the triangle, which is the same line as the diagonal. 7(7)+ 10(10)= diagonal x diagonal 149= diagonal x diagonal Diagonal= square root of 149: this approximates to 12.207in Visit quickanswerz.com for more math help/tutoring! Consider a rectangle with dimensions 7 inches by 10 inches. Let ABCD be the rectangle. We need to find the length of the diagonal. We know that the diagonals of a rectangle are same in length. So, it is enough to find the length of the diagonal BD. From the rectangle ABCD, it is clear that the triangle BCD is a right angled triangle. So, we can find the length of the diagonal using the Pythagorean Theorem. BD2 = BC2 + DC2 BD2 = 102 + 72 BD2 = 100 + 49 BD2 = 149 BD = √149 BD = 12.207 So, the length of the diagonal is 12.21 inches. Source: www.icoachmath.com
What is the the length of the diagonal of a 10 cm by 15 cm rectangle?
Use Pythagoras: diagonal² = length² + width² → diagonal² = (10 cm)² + (15 cm)² → diagonal = √(10² + 15²) cm = √325 cm = 5 √13 cm ≈ 18 cm
What is perimeter of a rectangle with a side of 8 and diagonal of 10?
To find the perimeter of a rectangle we need to know the length of its sides. P = 2L + 2W Let L = 8, and W = √(102 - 82) = √(100 - 64) = √36 = 6 (by the Pythagorean theorem, where the hypotenuse is the diagonal and legs are the sides of the rectangle). Thus, P = 2(8) + 2(6) = 16 + 12 = 28.
