The perimeter of the rectangle is the sum of all four side lengths. A rectangle has two pairs of congruent sides. Two sides are 8m each. That accounts for 16m of the perimeter. 22 - 16 = 6. So the other two sides must add up to 6m. Divide that amount in half since the sides are congruent. The width of the rectangle is 3m.
i come here to find the answer not answer it
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter
98 square feet
width=15 length=35
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
you need length and width length multiply width = area length + length + width + width = perimeter
Length + length + width + width = perimeter. Length + width x 2 = perimeter
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
You divide the perimeter by the width and you get the lenght
Length = (Perimeter - twice width) / 2
length 18 width 7
by appying 2l+2w
Perimeter = 2*(L + W).