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What are the dimensions if the perimeter is 124 feet and the length is 6 feet more than 3 times the width?
Wiki User
∙ 13y ago
Create an equation to solve the problem.
p=2l=2w
l=3w+6
the perimeter is 124. We substitute 124 for p and 3w+6 for l to reach the following solvable equation
124=2(3w+6)+2w
124=6w+12+2w (distribute the 2 over 3w+6)
124=8w+12 (combine like terms)
124-12=8w+12-12 (subtract 12 from both sides to isolate the variable w)
112=8w (combine like terms again)
112/8=8w/8 (divide both sides by 8 to isolate w)
14=w
We now know the width is 14 feet. We then substitute that value for w in the equation we wrote for the value of l
l=3w+6
l=3*14+6
l=42+6
l=48
The length is 48 feet. We can now substitute both values into the equation for perimeter to check our answer.
p=2w+2l
124=(2*14)+(2*48)
124=28+96
124=124
The result is true, so the result is correct.
Wiki User
∙ 13y ago
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