Acceleration = (change in speed) divided by (time for the change)
= (4.9) / 3 = 1.63 m/s2(rounded)
1.63 m/s2
Acceleration = (change in speed) divided by (time for the change).From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .There's no way that this is happening on the moon. That acceleration is about 67% greaterthan the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.I see the problem now. The '49' in the question should be '4.9'.apex- 1.63 m/s2
Gravitational potential energy describes how much energy a body has in store by virtue of having been elevated to a specific height. The formula to calculate gravitational potential energy is:.U = mgh.Where:U is the potential energym is the mass of the objectg is the acceleration due to gravity, andh is the height the object will fall if dropped.
Its acceleration is always the same - the acceleration of gravity at 32 ft/sec/sec - no matter what distance it is during drop, until it hits the ground.
Assuming that your units of velocity are in units/second Acceleration = (velocity 2 - velocity 1) / time Acceleration = (4.9 - 0) / 3 Acceleration =1.63 *With correct significant figures the answer is 2
1.63 m/s2
Acceleration = (change in speed) divided by (time for the change).From the figures given in the question, the acceleration is ( 49/3 ) = 16.33 m/sec2 .There's no way that this is happening on the moon. That acceleration is about 67% greaterthan the acceleration of gravity on the earth's surface. It should be about 83% less, or about 1.63 m/sec2.I see the problem now. The '49' in the question should be '4.9'.apex- 1.63 m/s2
The initial velocity of a dropped ball is zero in the y (up-down) direction. After it is dropped gravity causes an acceleration, which causes the velocity to increase. F = ma, The acceleration due to gravity creates a force on the mass of the ball.
If we disregard air resistance; they both have identical acceleration under gravity. If we take air resistance into account, then the mass that is fired will be de-accelerating slightly, so if you calculate the overall acceleration it will be slightly lower than the mass that is dropped.
9.8 m/s/s
As usual when we talk about falling objects, we have to ignore air resistance,because its effects depend on the size, shape, and composition of the objectthat's falling, as well as the temperature, pressure, humidity, and wind-speedof the local air, and we have none of that information. So we must simply treatthe whole subject as if the only effects on the falling object are those that arethe result of gravity.Velocity:-- The direction of the velocity vector is down.-- The magnitude of the velocity vector (called "speed") is(initial downward speed when dropped or tossed) plus (acceleration x time spent falling).Acceleration:-- Direction of the acceleration vector is down.-- Magnitude of the acceleration vector depends on what planet you're on or near,but is always the same as long as you stay there, and doesn't need to be calculated.In the case of Earth, it's 9.8 meters (32.2 ft) per second2 .
Gravitational potential energy describes how much energy a body has in store by virtue of having been elevated to a specific height. The formula to calculate gravitational potential energy is:.U = mgh.Where:U is the potential energym is the mass of the objectg is the acceleration due to gravity, andh is the height the object will fall if dropped.
If the increase in speed is uniform, this means that the slope of the function of speed over time is constant. This means that acceleration is constant.
The acceleration is the same, which is the acceleration due to gravity. About 10m/s^2
The bullet fired from a gun has greater horizontal acceleration. For vertical acceleration, they are both the same.
That works out at an acceleration of 1.63 m/s2(Presumably you meant 8.15 meters per second.)You would measure how far the rock dropped in 5 seconds. Then you could work out the final speed (or acceleration) from the "equations of motion".
Acceleration due to the force of gravity.