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Area of trapezoid: 0.5*(5+3)*3 = 12 square cm

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How do you find the second base of a trapezoid when given the first base the height and the area?

Let the second base be x: 0.5*(first base+x)*height = area x = (2*area/height) - first base


What is the area of a trapezoid with base of 4Cm and 28Cm?

The height of the trapezoid is also needed to find its area which is as follows:- Area of a trapezoid = 0.5*(sum of bases or parallel sides)*height


Is the area of a trapezoid equal to the products of the height and the length of the midsegment?

Area of a trapezoid = 0.5*(sum of parallel sides)*height


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Area of a trapezoid: 0.5*(sum of its parallel sides)*height


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Area of a trapezoid = 0.5*(sum of parallel side)*height


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Area of a trapezoid: 0.5*(sum of parallel sides)*height


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Area of a trapezoid = 0.5*(sum of parallel sides)*height


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Area of a trapezoid = 0.5*( sum of parallel sides)*height


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Area of a trapezoid: 0.5*(sum of parallel sides)*height


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Area of a trapezoid = 0.5*(sum of parallel sides)*height


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The area of a trapezoid is equal to the height, multiplied by the average of the two widths.