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Using the dsitance formula it is the square root of 26 which is about 5.099 to 3 decimal places
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How do you calculate the distance between two cubes?
The distance from n^3 to the next cube is 3n^2 + 3n + 1.
What is the distance between 7 1 and 7 3 on a coordinate plane?
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between these 2 points -3 -1 and 5 -1?
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
How do you calculate the distance between two cubes?
The distance from n^3 to the next cube is 3n^2 + 3n + 1.
What is the distance between 7 1 and 7 3 on a coordinate plane?
The distance between two points on a coordinate plane is calculated using the distance formula: Distance = √((x2 - x1)^2 + (y2 - y1)^2) In this case, the coordinates of the two points are (7, 1) and (7, 3). Since the x-coordinates are the same, we only need to calculate the difference in the y-coordinates, which is (3 - 1) = 2. Plugging this into the distance formula gives us: Distance = √((0)^2 + (2)^2) = √4 = 2. Therefore, the distance between the two points is 2 units.
How do you calculate acceleration from velocity?
There are 3 formula 1. Final velocity = starting velocity + (acceleration)(time) 2. Final velocity^2 = starting velocity^2 + 2(acceleration)(distance) 3. Distance = (starting velocity)(time) + 1/2(acceleration)(time^2) Use whichever you can use.
What is the distance of (-5. 5 2. 3) to (1. 2 2. 3)?
3 1/2
What is the average speed of a car that travels 40mph for 1 hour and 60 mph in another hour?
For this type of problem, you need to:(1) calculate the total distance elapsed, (2) calculate the total time elapsed, (3) divide the result of (1) by the result of (2).
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between these 2 points -3 -1 and 5 -1?
(-3-5)2+(-1--1)2 = 64 and the square root of this is the distance which is 8
What is the distance between the points -4 3 and 3 -1?
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
How do you calculate the area of three trig beacons making a triangle?
The trig beacons are basically points on a grid. Let's name these beacons (1), (2), (3). They all have coordinates of the form (x,y). Using the distance formula, √[(x2-x1)2+(y2-y1)2], calculate the distance between (1) and (2) [call it A], (1) and (3) [call this B], (2) and (3) [call it C]. Calculate the semiperimeter, which would be (A+B+C)/2. Call this S. Using Heron's formula, the area of the triangle is √[S(S-A)(S-B)(S-C)].
A person walks 3 miles north, turns and walks 2 miles east. Calculate the persons distance traveled and their displacement?
Distance 2+3=5 displacement 2
What is the distance between points 1 -1 and -3 5?
distance = sqrt( (xf-xi)2 + (yf-yi)2 ) = sqrt( ((-3) - (1))2 + ((5) - (-1))2 ) = sqrt(52)
What is the slope of the points (-3-1) and (3-2)?
Points: (-3, -1) and (3, -2) Slope: -1/6
