There's no root and there's no variable, so no, it can't be factored, but it can be simplified to 113.
It is: 4-16x2 = (2-4x)(2+4x) when factored
It is (4x-3)(4x+3) when factored
This quadratic expression can't be factored because its discriminant is less than zero.
If that's 16x2 + 72x + 81, that factors to (4x + 9)(4x + 9) or (4x + 9)2
It is 8(80b+81) when factored
x2-18x+81 = (x-9)(x-9) when factored
D.4(2x - 3)(2x + 1)
16x2 + 32x - 65 = 0 factorises (4x + 13)(4x - 5) This makes x either -13/4 or 5/4.
-16x2 + x + 8 = -1/64(32x - 1 - √513)(32x - 1 + √513)
16x2 - 56x + 49 = (4x - 7)2
16x2 + 40x + 25 = 16x2 + 20x + 20x + 25 = 4x(4x + 5) + 5(4x + 5) = (4x + 5)(4x + 5) = (4x + 5)2
Divide all terms by 3 and so x2+18x+81= (x+9)(x+9) when factored