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Yes because they comply with Pythagoras' theorem.
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Can 16 30 and 34 be a triangle leangth?
No. But they can be the lengths (not leangths!) of the three sides.
The legs of a triangle are 5 and 12 What is the perimeter?
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
What is the third side of a triangle when one side is 16 and the outher is 30?
If its a right angle it will be 34 units in length because it complies with Pythagoras' theorem.
The measures of two sides of a triangle are 22 and 34 Which measure is possible for the third side?
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
What is the hypotenuse and perimeter of a right angle triangle when one side is 14 cm greater than the other side with an area of 240 square cm showing work?
1 Let the sides be x+14 and x 2 So: 0.5*(x+14)*x = 240 which transposes to x2+14x-480 3 Solving the above quadratic equation gives x a positive value of 16 4 Therefore the sides are 30 and 16 5 Using Pythagoras: 302+162 = 1156 and its square root is 34 6 Hypotenuse = 34 cm 7 Perimeter = 34+30+16 = 80 cm
Can 16 30 and 34 be a triangle leangth?
No. But they can be the lengths (not leangths!) of the three sides.
A triangle with lengths of 16 30 and 35 a right angle?
A triangle whose sides are 16, 30, and 35 in length is not a right triangle, becausethe square of the length of the longest side is not equal to the sum of the squaresof the lengths of the other two sides.But if the 35 were a 34 instead, then it wouldbe.
Can the sides of a right triangle be 16 30 and 34 in?
To test use PYTHAGORAS ; h^2 = a^2 + b^2 34' is the longest side (h) , hence 34^(2) = 1156 a & b are 16 & 30 Hence 16^() + 30^(2) = 256 + 900 = 1156 , which equatres with 34^(2) . Thereby satisfies the Pythagorean Equation. Hence it is a Right angled triangle. So the sides 16,30, & 34 form a right triangle.
The legs of a triangle are 5 and 12 What is the perimeter?
With sides of 5 and 12, you can make a triangle with any perimeter you want between 24 and 34. If you call them "legs" because they are the sides of a right triangle, then the hypotenuse is 13, and the perimeter is 30.
What are the x solutions for 4x²-30 equals 34?
4x2 - 30 = 34 Add 30 to both sides 4x2 = 64 Divide both sides by 4 x2 = 16 Take the square root of both sides: x = 4 or -4
What is the length of a hypotenuse of a right triangle with legs 16 and 30?
c2 = a2 + b2, where c is the hypotenuse, and a and b are the other two sides. c2 = 162 + 302 c2 = 1156 √c2 = √1156 c = 34
When two sides of an isosceles triangle are 34 and the height is 30 what is the base's length?
The length is 32. Since an isosceles triangle is symmetrical, the height divides it into two right triangles. The hypotenuse of one of these triangles is 34, one of the legs is 30 (the height), and the other leg is half of the base, which we'll call x. Using the Pythagorean Theorem, we know x^2+30^2=34^2, or x^2+900=1156. This gives us x^2=256, or x=16 (it could also be -16, but this is absurd because it's a length). We said x was half the base, so the base itself is 2x=2*16=32.
How do you find the length of the base of an isoceles triangle when both sides are 34cm and the height is 30cm?
pythagoreon thereom 34sq - 30sq = 256 sqrt = 16 base 16+16 = 32 half length of base = SQR(34^2 - 30^2) =SQR(1156-900) =SQR(256) =16 base length = 2x 16=32
What is the third side of a triangle when one side is 16 and the outher is 30?
If its a right angle it will be 34 units in length because it complies with Pythagoras' theorem.
The measures of two sides of a triangle are 22 and 34 Which measure is possible for the third side?
Doesn't it depend on what type of triangle it is? And which sides you are measuring? And which side it's laying on?
Which could be the measures of the sides of a right triangle?
65, 72, and 97
What is the hypotenuse and perimeter of a right angle triangle when one side is 14 cm greater than the other side with an area of 240 square cm showing work?
1 Let the sides be x+14 and x 2 So: 0.5*(x+14)*x = 240 which transposes to x2+14x-480 3 Solving the above quadratic equation gives x a positive value of 16 4 Therefore the sides are 30 and 16 5 Using Pythagoras: 302+162 = 1156 and its square root is 34 6 Hypotenuse = 34 cm 7 Perimeter = 34+30+16 = 80 cm
