No because its discriminant is less than zero
x2+x-6 = (x-2)(x+3) when factored
x2 + 5x + 6 = (x + 2)(x + 3)
It is: (x+3)(x+4) when factored
14
It is (x-3)(x-4) when factored
(x - 3)(x - 2)
x3 - x2 + 2x = x*(x2 - x + 2) which cannot be factored further.
x - 3
x2+2x-15 = (x+5)(x-3) when factored
x^2 +7x+12 = (x+3)(x+4) when factored
It is: x^2 +11x +24 = (x+8)(x+3) when factored
x2+5x+6 = (x+2)(x+3) when factored because 2 and 3 are factors of 6