x2 - 11x + 24 = (x - 3)(x - 8)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6
-x2 - 11x + 26 = -(x2 + 11x - 26) = -(x2 - 2x + 13x - 26) = -[ x(x - 2) + 13(x - 2) ] = -(x + 13)(x - 2) = (x + 13)(2 - x)
572 Because 2x11=22 and 13x2=26 and 22x26=572.
The factors of (x2 + 11x + 30) are (X + 5) and (x + 6)You want to look for two numbers, when multiplied equal 30, and when added equal 11. Start with factors of 30, and see what they add to: 5+6=11, and 5*6=30.
x2 - 11x + 24 = (x - 3)(x - 8)
If you mean x2+11x+24 then it is (x+3)(x+8) when factored
x2 + 11x + 24 You want the equation to be in the form (x + a)(x + b), where the two solutions are -a and -b.You know that...ab = 24...and...a + b = 11Note that 8 times 3 is 24, and 8 plus 3 is 11.x2 + 11x + 24 = (x + 3)(x + 8)The two answers are x = -3 and x = -8.
x^3 - 121x
X2 -11x +10=(x - 1 )(x - 10)
Not possible to be specific since you have not provided the sign of the term in x, but there are two possible factorisations; (x + 3)(x + 8) = x2 + 11x + 24 and (x - 3)(x - 8) = x2 - 11x + 24
x + 35 doesn't factor. If you meant x2 + 11x + 24, the answer is (x + 8)(x + 3)
x^2 + 11x + 6 has no rational zeros.
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
X2+11x+11 = 7x+9 X2+11x-7x+11-9 = 0 x2+4x+2 = 0 Solve as a quadratic equation by using the quadratic equation formula or by completing the square: x = -2 + or - the square root of 2
Assuming the question is written as: x2+11x-12 This would factor to: (x+12)(x-1)
x2 + 11x + 30 = 0 (x + 5)(x + 6) = 0 so the roots are -5 and -6