first eats some pie, then calculate Pie (mathematical wise). Then start writing and then take a pencil and eat it. Then your answer will be on your pilllow at 7:30am in 2 weeks
"Sum" requires at least two numbers. So there cannot be athree digit number that sums to anything.
To find the two-digit numbers whose digits sum to a perfect square, we first identify the possible sums of the digits, which range from 1 (1+0) to 18 (9+9). The perfect squares in this range are 1, 4, 9, and 16. The valid two-digit combinations for these sums are: for 4 (14, 23, 32, 41, 50), for 9 (18, 27, 36, 45, 54, 63, 72, 81, 90), and for 16 (79). Counting all valid combinations gives us a total of 20 two-digit numbers.
Basically, it means to add the numbers in your head.
Digits: 0, 1, 2, 3, 4, 5, 6, 7, 8, and 9. The sum of all digits is 45.
Sure! Three addition facts that have sums that are odd numbers are: 1+1=2 (even), 2+1=3 (odd), 3+3=6 (even).
you can make at least 25 sums
To give mathematical completeness; it enables all sums to be solvable, (even if this just means proving that they have no answer) in the same way that inventing "negative numbers", "zero" and "imaginary numbers" enable all maths to be solvable. (Not that all sums have answers).
you have to add
Difference between the sum of the squares and the square of the sums of n numbers?Read more:Difference_between_the_sum_of_the_squares_and_the_square_of_the_sums_of_n_numbers
No.
Infinitely many. 12+11, 13+10, 14+9, ... , 22+1, 23+0, 24+(-1), 25+(-2), ... and then you have sums with numbers to one decimal place (dp) such as 11.6+11.4, and so on. Not forgetting numbers to 2 dp, 3, dp, 4, dp, ... , infinitely many dp. But these are only sums of two numbers. There are sums of 3 numbers, 4 numbers, ... infinitely many.
average function