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Using the point (x1, y1) = (4, -3) and the slope m = 1, we have:
(y - y1) = m(x - x1) substitute the given values:
(y - -3) = 1(x - 4)
(y + 3) = (x - 4) this is the point-slope form of the equation of a line.
y + 3 = x - 4 subtract 3 to both sides
y = x - 7 this is the slope intercept form, and
-x + y = -7 is the general form
What else can I help you with?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
How do you find point-slope form?
The point slope form of a line is one that contains the point and the slope. It is (y-y1)=m(x-x1) Where (x1,y1) are the point on the line that you are given. The other (x,y) are any x and y and m is the slope. So if we have a point (1,2) just for example, and a slope m=3, then the point slope equation or form is (y-2)=3(x-1) Note: The point slope form is easy to remember. It comes directly from the definition of slope. The slope is the rise over the run, of (change in y values) divided (change in x values) Now call the slope m, and let a point we know be (x1,y1) and any other point on the line (x,y), then the slope is m=(y-y1)/(x-x1). Now multiply both sides by (x-x1) and you have the point slope form.
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
What is the equation in point-slope form of the line that has a slope of 6 and passes through the point 1 8?
It is: y = 6x+18 whereas 6 is the slope and 18 is the y intercept
How do you translate ordered pairs into an equation?
If you have a pair of coordinates you can find the slope then put it into either point slope or slope intercept form. (2,3) and (5,4) has a slope of (3-2)/2-4) or 1/-2 or -1/2 Then you can put that in y-3=-1/2(x-2) as point slope or y=-1/2(x) + b 3=-1/2(2) + b 4=b therefore y=-1/2x+4
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point 1 1?
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
What is the point-slope form of a line that has a slope of 3 and passes through point 1 4?
If: slope is 3 and point is (1, 4) Then: y = 3x+1
What is the point slope form of a line that has a slope of 3 and passes through point 1 4?
If: slope is 3 and point is (1, 4) Then: y = 3x+1
What is the point-slope form of a line with a slope -5 that contains the point (2-1)?
Point: (2, -1) Slope: -5 Equation: y = -5x+9
What is the equation of the line that passes through 2 4 and 1 -3 in slope-intercept form?
(2,4) (1, -3) First, find the slope, which is change in y over change in x. from -3 to 4 is 7 from 1 to 2 is 1 The slope is 7. Using the point slope formula you can find it in slope-intercept form. point-slope is y-y1=m(x-x1) *Number 1's are subscripts and m=slope* [You use a point for y1 and x1] y- (-3) = 7 (x-1) y+3 = 7x - 7 y= 7x -10
What is the point-slope form of a line with slope 3 that contains the point (2 1)?
y-1 = 3(x - 2)
What is the point-slope form of the equation of a line that passes through the point (1 4) and has a slope of and minus3?
Point: (1, 4) Slope: -3 Equation: y = -3x+7
How do you find point-slope form?
The point slope form of a line is one that contains the point and the slope. It is (y-y1)=m(x-x1) Where (x1,y1) are the point on the line that you are given. The other (x,y) are any x and y and m is the slope. So if we have a point (1,2) just for example, and a slope m=3, then the point slope equation or form is (y-2)=3(x-1) Note: The point slope form is easy to remember. It comes directly from the definition of slope. The slope is the rise over the run, of (change in y values) divided (change in x values) Now call the slope m, and let a point we know be (x1,y1) and any other point on the line (x,y), then the slope is m=(y-y1)/(x-x1). Now multiply both sides by (x-x1) and you have the point slope form.
What is the point-slope form of a line with slope that contains the point (-2 1)?
The equation of the line will also depend on its slope which has not been given and so an answer is not possible.
If a line has a slope of 3 and contains the point (-14) what is it equation in point slope form?
Slope 3 and point of (-1, 4)Equation: y-4 = 3(x--1) => y = 3x+7
Write the equation in slope intercept form of the line that has a slope of 2 and contains the point 1 1?
y = 2x - 1
Find equation perpendicular to given line contain given point?
If you know the slope of the line that your equation is perpendicular too, you find the negative reciprocal of it and use it as the slope for the line. (negative reciprocal = flip the slope over and change its sign. Ex: a slope of 2 has a negative reciprocal of -1/2. ) Then you use the given point, and put your equation in point-slope form. The general equation for point slope form is Y-y1=m(x-x1) The y1 is the y coordinate of the given point. X1 is the x coordinate of the given point. M is the slope that you found earlier. You now have your equation. If you are asked to put it in slope intercept form, simply distribute the numbers and solve the equation for y.
