Q: Write the equation in slope intercept form of the line that has a slope of 2 and contains the point 1 1?

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It is: y = 2x-6

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

y=2x+13

Well. Slope intercept is y= mx + b. With B being the y intercept. If it contains 1,1 and the slope is positive 6, do the equation 1 = 6 (1) + b. 1 = 6 + b -5 = b. So the answer is y = 6x - 5

The point (0, -5) is the y-intercept (x = 0)

Related questions

Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).

y=2x+1

The answe iss..... 6

It is: y = 2x-6

y-9 = 3(x-4) y = 3x-3 in slope intercept form

No, you need either two points, one point and a slope, one point and a y-intercept, or a y-intercept an a slope. You can also write the equation of a line with an equation of another line but you would have to know if it is parallel or perpendicular.

The equation is (y - 1) = 2(x - 1) or, y = 2x - 1

Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).

It is: y-7 = 2(x-3) => y = 2x+1

As a straight line equation: y = -3x+18 in slope intercept form

plug in the slope(m) and coordinates (x,y) into the slope-intercept formula & solve for b.slope-intercept formula: y=mx+b

y- -5 = -3(x-4) y = -3x+12-5 y = -3x+7 in slope intercept form