The amplitude is ' 1 ' .
The amplitude is 4 .
amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period
cos x - 0.5 = 0 ⇒ cos x = 0.5 ⇒ x = 2nπ ± π/3
No, but cos(-x) = cos(x), because the cosine function is an even function.
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
The amplitude is 4 .
The amplitude of the wave [ y = -2 sin(x) ] is 2.
amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period
cos x - 0.5 = 0 ⇒ cos x = 0.5 ⇒ x = 2nπ ± π/3
No, but cos(-x) = cos(x), because the cosine function is an even function.
cos x equals cos -x because cos is an even function. An even function f is such that f(x) = f(-x).
cos(x)-cos(x)sin2(x)=[cos(x)][1-sin2(x)]cos(x)-cos(x)sin2(x)=[cos(x)][cos2(x)]cos(x)-cos(x)sin2(x)=cos3(x)
The amplitude is 1.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
sec(x)=1/cos(x), by definition of secant.
The amplitude of a function is half the distance between the maximum and minimum values. This is the absolute value of the number in front of the trig function. for example, y=Asin(x) or y= Acos(x) the absolute value of A is the amplitude. Therefore, the amplitude of y=-2sinx is 2
cos(60) = 0.57 x 60 x cos(60) = 7 x 30 = 210