0
The amplitude of a function is half the distance between the maximum and minimum values. This is the absolute value of the number in front of the trig function.
for example,
y=Asin(x) or y= Acos(x)
the absolute value of A is the amplitude.
Therefore, the amplitude of y=-2sinx is 2
Add your answer:
Earn +20 pts
What is the amplitude for y equals sin x divided by 2?
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
Why is 2 the answer for amplitude of y equals -2 sin x?
4
How do you prove this trigonometric relationship sin3A equals 3sinA cos 2 A - sin 3 A?
sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)
What is the period and amplitude for y equals 7 cos 2x?
amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period
Phase shift of y equals sin x-2?
Shift = +2
Determine the amplitude of y equals -2 sin x?
The amplitude of the wave [ y = -2 sin(x) ] is 2.
Determine the amplitude of y-2 sin x?
The amplitude is |-2| = 2.
Find the amplitude and period of the functions and sketch their graphs y equals sin -x?
y = sin(-x)Amplitude = 1Period = 2 pi
What is the amplitude for y equals sin x divided by 2?
Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.
What is the amplitude for the function y equals 6sinx?
The amplitude of the function [ sin(x) ] is 1 peak and 2 peak-to-peak . The amplitude of 6 times that function is 6 peak and 12 peak-to-peak.
Why is 2 the answer for amplitude of y equals -2 sin x?
4
What is the trig function of sin with a period of pi an amplitude of 1 and a vertical shift up of 1?
If this is a homework question, please consider trying to answer it on your own first, otherwise the value of reinforcement of the lesson will be lost on you. To determine the trigonometry function of sin, with a period of pi, and amplitude of 1, and a vertical shift of +1, start simple and expand. The period of sin(x) is 2 pi, so to halve that period you need sin(2x). The amplitude of sin(2x) is 2, so to halve that amplitude you need 1/2 sin(2x). To shift any function up by 1, simply add 1 to it, so the final answer is 1/2 sin(2x) + 1. Note: This is very simple when you take it step by step.
How do you find the amplitude maximum minimum and period for y equals -1 plus 3sin4x?
y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.
Can you make a meaningful sentence using the word amplitude?
1. The amplitude of the graph y=sin(x) is equal to 1. 2. The amplitude of the situation was greater than he anticipated.
What is the amplitude when you are given the mass and period and position of the oscillator and the velocity of the oscillator?
The amplitude of the oscillator cannot be determined solely from the mass, period, position, and velocity. The amplitude is dependent on the energy of the system, which is related to the initial conditions and the physical properties of the oscillator. Additional information about the specific physical system is needed to determine the amplitude.
How do you prove this trigonometric relationship sin3A equals 3sinA cos 2 A - sin 3 A?
sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)
Cos 60 equals and sin 60 equals?
cos60= 1/2 sin60=1.732/2
