Q: How do you determine that the amplitude of y equals -2 sin x?

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Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.

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sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)

amplitude =7. to find the period, set 2x equal to 2∏. then x=∏=period

Shift = +2

Related questions

The amplitude of the wave [ y = -2 sin(x) ] is 2.

The amplitude is |-2| = 2.

y = sin(-x)Amplitude = 1Period = 2 pi

Assuming the question refers to [sin(x)]/2 rather than sin(x/2) the answer is 1.

The amplitude of the function [ sin(x) ] is 1 peak and 2 peak-to-peak . The amplitude of 6 times that function is 6 peak and 12 peak-to-peak.

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If this is a homework question, please consider trying to answer it on your own first, otherwise the value of reinforcement of the lesson will be lost on you. To determine the trigonometry function of sin, with a period of pi, and amplitude of 1, and a vertical shift of +1, start simple and expand. The period of sin(x) is 2 pi, so to halve that period you need sin(2x). The amplitude of sin(2x) is 2, so to halve that amplitude you need 1/2 sin(2x). To shift any function up by 1, simply add 1 to it, so the final answer is 1/2 sin(2x) + 1. Note: This is very simple when you take it step by step.

y = -1 + 3 sin 4xLet's look at the equation of y = 3 sin 4x, which is of the form y = A sin Bx, wherethe amplitude = |A|, and the period = (2pi)/B.So that the amplitude of the graph of y = 3 sin 4x is |3| = 3, which tell us that the maximum value of y is 3 and the minimum value is -3, and the period is (2pi)/4 = pi/2, which tell us that each cycle is completed in pi/2 radians.The graph of y = -1 + 3 sin 4x has the same amplitude and period as y = 3 sin 4x, and translates the graph of y = 3 sin 4x one unit down, so that the maximum value of y becomes 2 and the minimum value becomes -4.

1. The amplitude of the graph y=sin(x) is equal to 1. 2. The amplitude of the situation was greater than he anticipated.

The amplitude of the oscillator cannot be determined solely from the mass, period, position, and velocity. The amplitude is dependent on the energy of the system, which is related to the initial conditions and the physical properties of the oscillator. Additional information about the specific physical system is needed to determine the amplitude.

cos60= 1/2 sin60=1.732/2

sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)