cos(60) = 0.5
7 x 60 x cos(60) = 7 x 30 = 210
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sec(x)=1/cos(x), by definition of secant.
Cos(90 - x) = sin(x) so cos2(90 - x) = sin2(x)
cos x - 1 = 0 cos(x) = 1 x = 0 +/- k*pi radians where k = 1,2,3,...
22
That means you must take the derivative of the derivative. In this case, you must use the product rule. y = 6x sin x y'= 6[x (sin x)' + (x)' sin x] = 6[x cos x + sin x] y'' = 6[x (cos x)' + (x)' cos x + cos x] = 6[x (-sin x) + cos x + cos x] = 6[-x sin x + 2 cos x]