3 sec23x
sec^2(x)
d/dx(cos x) = -sinx
Suppose you wish to differentiate x/f(x) where f(x) is a differentiable function of x, and writing f for f(x) and f'(x) for the derivative of f(x), d/dx (x/f) = [f - x*f']/(f2)
y = Sin(x) dy/dx = Cos(x)
If you mean x squared + 9, you differentiate this as follows: Use the differentiation formula for a power, to differentiate the x squared. Separately, use the differentiation formula for a constant, to differentiate the 9. Finally, use the differentiation formula for a sum to add up the parts.
Differentiate it term by term.Each term of a polynomial is of the form a*x^n where a is a constant and n is a non-negative integer.So, the derivative of such a term is a*n*x^(n-1).
x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
The deriviative of sin2 x + cos2 x is 2 cos x - 2 sin x
The derivative of ( x1/2 ) with respect to 'x' is [ 1/2 x-1/2 ], or 1/[2sqrt(x)] .
If you actually mean "... with respect to x", and that y is equal to this function of x, then the answer is:y = x sin(x)∴ dy/dx = sin(x) + x cos(x)
Differentiating x^2 can be accomplished by using the Power Rule. This provides that d/dx (x^2)=2x
d/dx(x + 2) = d/dx(x) + d/dx(2) = 1 + 0 = 1