If you actually mean "... with respect to x", and that y is equal to this function of x, then the answer is:
y = x sin(x)
∴ dy/dx = sin(x) + x cos(x)
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x = yy differentiate both sides with respect to x dx = (y * yy-1) dy dy/dx = y * yy-1 dy/dx = yy = x hence differentiate of y wrt x is x only
y=sinx y=cosxsinx=cosx=>sinx/cosx=1=>tanx=1=>x=45oie.. y=sin45=cos45y=1/(square root of 2)
yes y=sinx is x=arcsiny
The differential of the product xy with respect to x is y + x dy/dx. The differential of logy with respect to x is (1/y) dy/dx. The role of c in this question is not made clear.
y=ax y'=ln(a)*ax