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A student claims that the equation -x 3 has no solution since the square root of a negative number does not exist Why is this argument wrong?
The equation does not have real solutions, but it has pure imaginary numbers as solutions. -x^2 = 3 multiply by -1 to both sides x^2 = - 3 x = ± √-3 x = ± √[(-1)(3)] substitute i^2 for -1 x = ± √[(i^2)(3)] x = ± (√3)i
Which equation has solution x -3?
The equation x = 3 has a solution of x = 3. This is because when you substitute x = 3 into the equation x = 3, it satisfies the equation and makes it true. Therefore, x = 3 is the equation with the solution x = 3.
What equation of 2 x -3?
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Which equation has the solution set 1 and 3?
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
What is the difference between an algebraic expression and an equation?
Equation: x+3=3+x (notice the equal sign: equal; equation)Expression: x+3 (notice no equal sign)
Example of the difference between equation and an expression?
Equation: x+3=3+x (notice the equal sign: equal; equation)Expression: x+3 (notice no equal sign)
What is the equation of ( 3 - 1 ) on a slope equation?
It is: y = x+3
How do you graph the equation x plus 3 equals 0?
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
Is y(x 1)(x-3) an equation for this parabola?
To determine if ( y = (x - 1)(x - 3) ) is an equation for a parabola, we can rewrite it in standard form. Expanding this gives ( y = x^2 - 4x + 3 ), which is indeed a quadratic equation representing a parabola. Therefore, yes, ( y = (x - 1)(x - 3) ) is an equation for a parabola.
How do you solve for x with this equation y equals -x plus 3?
Y = - X + 3 You must zero out the Y - X + 3 = 0 - x = - 3 X = 3 ------- If you graphed the original equation you would see that.
Does a solution to an equation make the equation true or false?
A solution to an question makes the equation true. For example a solution to the equation 3x = x + 6 is x = 3, since 3(3) = 3+6.
If a quadratic equation has roots at 3 and -5 which factors could be multiplied together to obtain an original equation?
(x - 3) and (x - (-5)).
