Probably.
The equation does not have real solutions, but it has pure imaginary numbers as solutions. -x^2 = 3 multiply by -1 to both sides x^2 = - 3 x = ± √-3 x = ± √[(-1)(3)] substitute i^2 for -1 x = ± √[(i^2)(3)] x = ± (√3)i
The equation x = 3 has a solution of x = 3. This is because when you substitute x = 3 into the equation x = 3, it satisfies the equation and makes it true. Therefore, x = 3 is the equation with the solution x = 3.
The equation ( x - 3 = 0 ) can be solved by isolating ( x ). By adding 3 to both sides of the equation, we find that ( x = 3 ). Thus, the solution to the equation is ( x = 3 ).
5
An equation with the solution set 1 and 3 can be written in factored form as (x-1)(x-3) = 0. When expanded, this equation becomes x^2 - 4x + 3 = 0. Therefore, the equation x^2 - 4x + 3 = 0 has the solution set 1 and 3.
The equation ( x - y = 3 ) represents a straight line in the coordinate plane. Since it is a linear equation with two variables, it has infinitely many solutions, as any point (x, y) on the line satisfies the equation. Specifically, for any value of ( y ), you can find a corresponding value of ( x ) such that the equation holds true.
Equation: x+3=3+x (notice the equal sign: equal; equation)Expression: x+3 (notice no equal sign)
Equation: x+3=3+x (notice the equal sign: equal; equation)Expression: x+3 (notice no equal sign)
It is: y = x+3
Move 3 over the right side of the equation so the equation would be x = -3. The graph of this would be a verticle line at x= -3
No, an equation with integer coefficients does not always have an integer solution. For example, the equation (x + 1 = 2) has an integer solution, (x = 1), but the equation (2x + 3 = 1) has no integer solution since (x = -1) is not an integer. Solutions depend on the specific equation and its constraints, and rational or real solutions may exist instead.
To determine if ( y = (x - 1)(x - 3) ) is an equation for a parabola, we can rewrite it in standard form. Expanding this gives ( y = x^2 - 4x + 3 ), which is indeed a quadratic equation representing a parabola. Therefore, yes, ( y = (x - 1)(x - 3) ) is an equation for a parabola.