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7(x^2)+33x-10
This is the way I would approach this problem.
Find the factors of the first and last number:
Factors of 7: 1,7
Factors of -10: -10,-5,-2,-1,1,2,5,10
Set up the two quantities:
(x +/- __)(7x +/- __ )
Figure out which factors of -10 when multiplied with the factors of 7 then added together will equal +33:
5(7)+(-2)=33
Therefore:
(x+5)(7x-2)
Double check answer by foiling:
(x+5)(7x-2)=7(x^2)-2x+35x-10
7(x^2)+33x-10
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∙ 14y ago
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