Factor 7x2 plus 33x-10

Answer 1

7(x^2)+33x-10

This is the way I would approach this problem.

Find the factors of the first and last number:

Factors of 7: 1,7

Factors of -10: -10,-5,-2,-1,1,2,5,10

Set up the two quantities:

(x +/- __)(7x +/- __ )

Figure out which factors of -10 when multiplied with the factors of 7 then added together will equal +33:

5(7)+(-2)=33

Therefore:

(x+5)(7x-2)

Double check answer by foiling:

(x+5)(7x-2)=7(x^2)-2x+35x-10

7(x^2)+33x-10